Variable Relationships - Math

Card 0 of 16

In a standard deck of cards, with replacement, what is the probability of drawing two Ace of Hearts?

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Probability of drawing first ace of hearts: $\frac{1}{52}$

Probability of drawing second ace of hearts: $\frac{1}{52}$

Multiply both probabilities by each other:

$\frac{1}{52}$*$\frac{1}{52}$=\frac{1}{2704}$

In a standard deck of cards, without replacement, what is the probability of drawing three kings?

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Start with 52 cards, probability of drawing first king: $\frac{4}{52}$

Now you have 51 cards. Probability of drawing second king: $\frac{3}{51}$

Now you have 50 cards. Probability of drawing third king: $\frac{2}{50}$

Multiply all probabilities:

$\frac{4}{52}$$\frac{3}{51}$$\frac{2}{50}$=\frac{24}{132,600}$=\frac{1}{5525}$

Using a standard deck of cards, what is the probability of choosing a single face card?

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There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards.

Thus the probability of choosing a single face card is $\frac{12}{52}$ or $\frac{3}{13}$ .

With a standard deck of cards, what is the probability of picking a spade then a red card if there is no replacement?

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In a standard deck of cards:

$P(spade)\cdot P(red)=\frac{13}{52}$\cdot $\frac{26}{51}$=\frac{13}{102}$$

In a standard deck of cards, with replacement, what is the probability of drawing two Ace of Hearts?

Tap to see back →

Probability of drawing first ace of hearts: $\frac{1}{52}$

Probability of drawing second ace of hearts: $\frac{1}{52}$

Multiply both probabilities by each other:

$\frac{1}{52}$*$\frac{1}{52}$=\frac{1}{2704}$

In a standard deck of cards, without replacement, what is the probability of drawing three kings?

Tap to see back →

Start with 52 cards, probability of drawing first king: $\frac{4}{52}$

Now you have 51 cards. Probability of drawing second king: $\frac{3}{51}$

Now you have 50 cards. Probability of drawing third king: $\frac{2}{50}$

Multiply all probabilities:

$\frac{4}{52}$$\frac{3}{51}$$\frac{2}{50}$=\frac{24}{132,600}$=\frac{1}{5525}$

Using a standard deck of cards, what is the probability of choosing a single face card?

Tap to see back →

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards.

Thus the probability of choosing a single face card is $\frac{12}{52}$ or $\frac{3}{13}$ .

With a standard deck of cards, what is the probability of picking a spade then a red card if there is no replacement?

Tap to see back →

In a standard deck of cards:

$P(spade)\cdot P(red)=\frac{13}{52}$\cdot $\frac{26}{51}$=\frac{13}{102}$$

In a standard deck of cards, with replacement, what is the probability of drawing two Ace of Hearts?

Tap to see back →

Probability of drawing first ace of hearts: $\frac{1}{52}$

Probability of drawing second ace of hearts: $\frac{1}{52}$

Multiply both probabilities by each other:

$\frac{1}{52}$*$\frac{1}{52}$=\frac{1}{2704}$

In a standard deck of cards, without replacement, what is the probability of drawing three kings?

Tap to see back →

Start with 52 cards, probability of drawing first king: $\frac{4}{52}$

Now you have 51 cards. Probability of drawing second king: $\frac{3}{51}$

Now you have 50 cards. Probability of drawing third king: $\frac{2}{50}$

Multiply all probabilities:

$\frac{4}{52}$$\frac{3}{51}$$\frac{2}{50}$=\frac{24}{132,600}$=\frac{1}{5525}$

Using a standard deck of cards, what is the probability of choosing a single face card?

Tap to see back →

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards.

Thus the probability of choosing a single face card is $\frac{12}{52}$ or $\frac{3}{13}$ .

With a standard deck of cards, what is the probability of picking a spade then a red card if there is no replacement?

Tap to see back →

In a standard deck of cards:

$P(spade)\cdot P(red)=\frac{13}{52}$\cdot $\frac{26}{51}$=\frac{13}{102}$$

In a standard deck of cards, with replacement, what is the probability of drawing two Ace of Hearts?

Tap to see back →

Probability of drawing first ace of hearts: $\frac{1}{52}$

Probability of drawing second ace of hearts: $\frac{1}{52}$

Multiply both probabilities by each other:

$\frac{1}{52}$*$\frac{1}{52}$=\frac{1}{2704}$

In a standard deck of cards, without replacement, what is the probability of drawing three kings?

Tap to see back →

Start with 52 cards, probability of drawing first king: $\frac{4}{52}$

Now you have 51 cards. Probability of drawing second king: $\frac{3}{51}$

Now you have 50 cards. Probability of drawing third king: $\frac{2}{50}$

Multiply all probabilities:

$\frac{4}{52}$$\frac{3}{51}$$\frac{2}{50}$=\frac{24}{132,600}$=\frac{1}{5525}$

Using a standard deck of cards, what is the probability of choosing a single face card?

Tap to see back →

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards.

Thus the probability of choosing a single face card is $\frac{12}{52}$ or $\frac{3}{13}$ .

With a standard deck of cards, what is the probability of picking a spade then a red card if there is no replacement?

Tap to see back →

Variable Relationships - Math

In a standard deck of cards, with replacement, what is the probability of drawing two Ace of Hearts?

Probability of drawing first ace of hearts: Probability of drawing second ace of hearts: Multiply both probabilities by each other:

In a standard deck of cards, without replacement, what is the probability of drawing three kings?

Start with 52 cards, probability of drawing first king: Now you have 51 cards. Probability of drawing second king: Now you have 50 cards. Probability of drawing third king: Multiply all probabilities:

Using a standard deck of cards, what is the probability of choosing a single face card?

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards. Thus the probability of choosing a single face card is or .

With a standard deck of cards, what is the probability of picking a spade then a red card if there is no replacement?

In a standard deck of cards:

In a standard deck of cards, with replacement, what is the probability of drawing two Ace of Hearts?

Probability of drawing first ace of hearts: Probability of drawing second ace of hearts: Multiply both probabilities by each other:

In a standard deck of cards, without replacement, what is the probability of drawing three kings?

Start with 52 cards, probability of drawing first king: Now you have 51 cards. Probability of drawing second king: Now you have 50 cards. Probability of drawing third king: Multiply all probabilities:

Using a standard deck of cards, what is the probability of choosing a single face card?

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards. Thus the probability of choosing a single face card is or .

With a standard deck of cards, what is the probability of picking a spade then a red card if there is no replacement?

In a standard deck of cards:

In a standard deck of cards, with replacement, what is the probability of drawing two Ace of Hearts?

Probability of drawing first ace of hearts: Probability of drawing second ace of hearts: Multiply both probabilities by each other:

In a standard deck of cards, without replacement, what is the probability of drawing three kings?

Start with 52 cards, probability of drawing first king: Now you have 51 cards. Probability of drawing second king: Now you have 50 cards. Probability of drawing third king: Multiply all probabilities:

Using a standard deck of cards, what is the probability of choosing a single face card?

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards. Thus the probability of choosing a single face card is or .

With a standard deck of cards, what is the probability of picking a spade then a red card if there is no replacement?

In a standard deck of cards:

In a standard deck of cards, with replacement, what is the probability of drawing two Ace of Hearts?

Probability of drawing first ace of hearts: Probability of drawing second ace of hearts: Multiply both probabilities by each other:

In a standard deck of cards, without replacement, what is the probability of drawing three kings?

Start with 52 cards, probability of drawing first king: Now you have 51 cards. Probability of drawing second king: Now you have 50 cards. Probability of drawing third king: Multiply all probabilities:

Using a standard deck of cards, what is the probability of choosing a single face card?

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards. Thus the probability of choosing a single face card is or .

With a standard deck of cards, what is the probability of picking a spade then a red card if there is no replacement?

In a standard deck of cards:

Probability of drawing first ace of hearts: $\frac{1}{52}$

Probability of drawing second ace of hearts: $\frac{1}{52}$

Multiply both probabilities by each other:

$\frac{1}{52}$*$\frac{1}{52}$=\frac{1}{2704}$

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards.

Thus the probability of choosing a single face card is $\frac{12}{52}$ or $\frac{3}{13}$ .

In a standard deck of cards:

$P(spade)\cdot P(red)=\frac{13}{52}$\cdot $\frac{26}{51}$=\frac{13}{102}$$

Probability of drawing first ace of hearts: $\frac{1}{52}$

Probability of drawing second ace of hearts: $\frac{1}{52}$

Multiply both probabilities by each other:

$\frac{1}{52}$*$\frac{1}{52}$=\frac{1}{2704}$

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards.

Thus the probability of choosing a single face card is $\frac{12}{52}$ or $\frac{3}{13}$ .

In a standard deck of cards:

$P(spade)\cdot P(red)=\frac{13}{52}$\cdot $\frac{26}{51}$=\frac{13}{102}$$

Probability of drawing first ace of hearts: $\frac{1}{52}$

Probability of drawing second ace of hearts: $\frac{1}{52}$

Multiply both probabilities by each other:

$\frac{1}{52}$*$\frac{1}{52}$=\frac{1}{2704}$

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards.

Thus the probability of choosing a single face card is $\frac{12}{52}$ or $\frac{3}{13}$ .

In a standard deck of cards:

$P(spade)\cdot P(red)=\frac{13}{52}$\cdot $\frac{26}{51}$=\frac{13}{102}$$

Probability of drawing first ace of hearts: $\frac{1}{52}$

Probability of drawing second ace of hearts: $\frac{1}{52}$

Multiply both probabilities by each other:

$\frac{1}{52}$*$\frac{1}{52}$=\frac{1}{2704}$

There are cards in a standard deck: cards in suits. There are face cards (King, Queen, Jack) in each suit, so there are total face cards.

Thus the probability of choosing a single face card is $\frac{12}{52}$ or $\frac{3}{13}$ .

In a standard deck of cards:

$P(spade)\cdot P(red)=\frac{13}{52}$\cdot $\frac{26}{51}$=\frac{13}{102}$$