Coordinate Geometry - Math

The slope of a perpendicular line is equal to the negative reciprocal of the original line. This means that the slope of our perpendicular line must be 3. We can also note that is also equal to 3, so both of these slopes are correct. The y-intercept does not matter, as the slope is the only thing that determines the slant of the line. Therefore, numerals I and III are both correct.

In order for two lines to be perpendicular to each other, their slopes must be opposites and reciprocals of each other, meaning the fraction must be flipped upside down and the signs must be changed. In this situation, the original equation had a slope of , so the perpendicular slope must be .

Two lines are perpendicular if they have opposite reciprocal slopes. When a line is in standard form, the is the slope. A perpendicular line will have a slope of .

The slope of our given line is . Therefore we want a slope of . The only line with the correct slope is .

The slope of a perpendicular line is equal to the negative reciprocal of the original line. This means that the slope of our perpendicular line must be 3. We can also note that is also equal to 3, so both of these slopes are correct. The y-intercept does not matter, as the slope is the only thing that determines the slant of the line. Therefore, numerals I and III are both correct.

In order for two lines to be perpendicular to each other, their slopes must be opposites and reciprocals of each other, meaning the fraction must be flipped upside down and the signs must be changed. In this situation, the original equation had a slope of , so the perpendicular slope must be .

Two lines are perpendicular if they have opposite reciprocal slopes. When a line is in standard form, the is the slope. A perpendicular line will have a slope of .

The slope of our given line is . Therefore we want a slope of . The only line with the correct slope is .

The coordinates form a triangle in the second quadrant with a side along the y-axis. The rotation about the origin by degrees clockwise results in a triangle in the first quadrant with a side along the x-axis. There are two responses that give triangles along the x-axis:

and

A rotation and a dialation by a factor of is given by

, so the correct answer is

The general equation of a circle is , where the center of the circle is and the radius is .

Thus, we plug the values given into the above equation to get .

The standard formula for a circle is , with the center of the circle and the radius.

Plug in our given information.

This describes what we are looking for. This equation is not one of the answer choices, however, so subtract from both sides.

First, calculate the slope of the line segment between the given points.

We want a line that is perpendicular to this segment and passes through its midpoint. The slope of a perpendicular line is the negative inverse. The slope of the perpendicular bisector will be .

Next, we need to find the midpoint of the segment, using the midpoint formula.

Using the midpoint and the slope, we can solve for the value of the y-intercept.

Using this value, we can write the equation for the perpendicular bisector in slope-intercept form.

Find the slope of the line through the two points. It is .

Since the slope of a perpendicular line is the negative reciprocal of the original line, the new line's slope is . Plug the slope and one of the points into the point-slope formula . Isolate for .

Since a perpendicular line has a slope that is the negative reciprocal of the original line, the new slope is . There is only one answer with the correct slope.

First, find the slope of the original line, which is . You can do this by isolating for so that the equation is in slope-intercept form. Once you find the slope, just replace the in the original equation withe the negative reciprocal (perpendicular lines have a negative reciprocal slope for each other). Thus, your answer is

In order for two lines to be perpendicular, their slopes must be opposites and recipricals of each other. The first step is to find the slope of the given equation:

Therefore, the slope of the perpendicular line must be . Using the point-slope formula, we can find the equation of the new line:

Perdendicular lines have slopes that are opposite reciprocals. The slope of the old line is , so the new slope is .

Plug the new slope and the given point into the slope intercept equation to calculate the intercept:

or , so .

Thus , or .

The equation is given in the slope-intercept form, so we know the slope is . To have perpendicular lines, the new slope must be the opposite reciprocal of the old slope, or

Then plug the new slope and the point into the slope-intercept form of the equation:

so so

So the new equation becomes: and in standard form

The coordinates form a triangle in the second quadrant with a side along the y-axis. The rotation about the origin by degrees clockwise results in a triangle in the first quadrant with a side along the x-axis. There are two responses that give triangles along the x-axis:

and

A rotation and a dialation by a factor of is given by

, so the correct answer is

First calculate the slope:

The standard equation for a line is .

In this equation, is the slope of the line, and is the -intercept. All points on the line must fit this equation. Plug in either point (1,3) or (2,2).

Plugging in (1,3) we get .

Therefore, .

Our equation for the line is now:

To find the -intercept, we plug in :

Thus, the -intercept the point (4,0).

We want to find the x-intercept, which is the point at which the graph crosses the x-axis. Every point on the x-axis has a y-value of 0. Thus, to find the x-intercept we just need to plug 0 in for y.

Thus, .

Dividing both sides by , we get .

To find the y-intercept, let equal 0.

We can then solve for the value of .

The y-intercept will be .