How to find the answer from a table - ISEE Middle Level Quantitative Reasoning

The quickest way to solve this problem is by making a chart showing the units purchased and the total cost. Start with the 4-packs of umbrellas:

4-packs cost shipping cost total cost

1 \$25 \$6 \$31

2 \$50 \$9 \$59

3 \$75 \$12 \$87

4 \$100 \$15 \$115

5 \$125 \$21 \$146 (too high)

Having determined that Katie can buy four of the 4-packs of umbrellas, now we see how many of the \$7 individual umbrellas she can add to her order.

four 4-packs indiv. indiv. $ subtotal shipping $ total $

\$100 1 \$7 \$107 \$18 \$125

\$100 2 \$14 \$114 \$18 \$132

\$100 3 \$21 \$121 \$21 \$142 (too high)

Therefore, Katie can buy (4) 4-packs and (2) individual umbrellas (18 total umbrellas) for \$132.

ALTERNATIVELY, you can begin by determining the highest subtotal she can afford and work backwards from there. \$120 is 6 x \$20, so the shipping charge would be \$6 x 3 = \$18, for a total cost of \$138. One more dollar on the subtotal would bring it into the next \$20 segment, bringing the shipping charge up to \$21 (and \$142 is greater than \$140). Thus, from here you could figure out the maximum number of \$25 4-packs and \$7 individual umbrellas Katie could buy with \$120.

Since \$6 is not enough to buy any umbrellas, the total would be

The population of Buchanan City in 1960 is greater than it was in 1940, so its decline between 1940 and 1950 must be less than its growth between 1950 and 1960.

No information about the population of Buchanan City is given for either 1965 or 1975.

(a) Between 1930 and 1940, the population grew by

(b) Between 1950 and 1960, the population grew by .

This makes (b) greater

Since the population of Buchanan City increased by at least 300 over each of three decades since 1980, then the population in 2010 is at least

.

Since the population has not decreased since 1980, it can be inferred that the population in 2010 was greater than or equal to that in 1980, which is 4,275. However, nothing more is known.

(a) 81% of 2,984 is

(b) 61% of 4,275 is

(b) is greater

Each square represents students. Mr. Ray's bar has squares in it. That means we can take to find our total.

Each square represents students. Ms. Smith's bar has squares in it. That means we can take to find our total.

Each square represents students. Ms. Hen's bar has 2 squares in it. That means we can take to find our total.

Each square represents students. Ms. Miller's bar has squares in it. That means we can take to find our total.

Each square represents students. Mr. Ray's bar has squares in it, which means he has students with pets (). Ms. Hen's bar has squares in it, which means she has students with pets ().

To find the difference we subtract.

Each square represents students. Mr. Ray's bar has squares in it, which means he has students with pets (). Ms. Milers bar has squares in it, which means she has students with pets ().

To find the difference we subtract.

Each square represents students. Ms. Smith's bar has squares in it, which means she has students with pets (). Mr. Ray's bar has squares in it, which means he has students with pets ().

To find the difference we subtract.

Each square represents students. Ms. Smith's bar has squares in it, which means she has students with pets (). Ms. Hen's bar has squares in it, which means she has students with pets ().

To find the difference we subtract.

Each square represents students. Ms. Smith's bar has squares in it, which means she has students with pets (). Ms. Miller's bar has squares in it, which means she has students with pets ().

To find the difference we subtract.

Each square represents students. Ms. Miller's bar has squares in it, which means she has students with pets (). Ms. Hen's bar has squares in it, which means she has students with pets ().

To find the difference we subtract.

Each square represents students. Mr. Ray's bar has squares in it, which means he has students with pets (). Ms. Hen's bar has squares in it, which means she has students with pets ().

To find the total in both classes we add.

Each square represents students. Ms. Smith's bar has squares in it, which means she has students with pets (). Ms. Hen's bar has squares in it, which means she has students with pets ().

To find the total in both classes we add.

Each square represents students. The first grade bar has squares in it. That means we can take to find our total.