Calculating whether point is on a line with an equation - GMAT Quantitative
Card 0 of 48
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug
into the
variable of the equation and solve for
:





To solve for for
, we have to plug
into the
variable of the equation and solve for
:
Compare your answer with the correct one above
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug 1 into the
variable of the equation and solve for
:






To solve for for
, we have to plug 1 into the
variable of the equation and solve for
:
Compare your answer with the correct one above
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug
into the
variable of the equation and solve for
:






To solve for for
, we have to plug
into the
variable of the equation and solve for
:
Compare your answer with the correct one above
Consider segment
which passes through the points
and
.
If the point
is on
, what is the value of y?
Consider segment which passes through the points
and
.
If the point is on
, what is the value of y?
First, use the points to find the equation of JK:
Given that JK passes through (4,5) and (144,75) we can find the slope as follows:
Slope is found via:

Plug in and calculate:

Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).


So our answer is:

To find y, we need to plug in 16 for x and solve:

First, use the points to find the equation of JK:
Given that JK passes through (4,5) and (144,75) we can find the slope as follows:
Slope is found via:
Plug in and calculate:
Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).
So our answer is:
To find y, we need to plug in 16 for x and solve:
Compare your answer with the correct one above
If
is defined as follows, is the point
on
?

If is defined as follows, is the point
on
?
To find out if (-2,5) is on f(x), simply plug the point into f(x)

Becomes,

So yes, it does!
To find out if (-2,5) is on f(x), simply plug the point into f(x)
Becomes,
So yes, it does!
Compare your answer with the correct one above
Which of the following are points along
if
.
Which of the following are points along if
.
One way to solve this one is by plugging in each of the answer choices and eliminating any that don't work out. Begin with our original g(x)

If we plug in 3 we get
,
So our point is (3,28).
One way to solve this one is by plugging in each of the answer choices and eliminating any that don't work out. Begin with our original g(x)
If we plug in 3 we get
,
So our point is (3,28).
Compare your answer with the correct one above
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug
into the
variable of the equation and solve for
:





To solve for for
, we have to plug
into the
variable of the equation and solve for
:
Compare your answer with the correct one above
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug 1 into the
variable of the equation and solve for
:






To solve for for
, we have to plug 1 into the
variable of the equation and solve for
:
Compare your answer with the correct one above
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug
into the
variable of the equation and solve for
:






To solve for for
, we have to plug
into the
variable of the equation and solve for
:
Compare your answer with the correct one above
Consider segment
which passes through the points
and
.
If the point
is on
, what is the value of y?
Consider segment which passes through the points
and
.
If the point is on
, what is the value of y?
First, use the points to find the equation of JK:
Given that JK passes through (4,5) and (144,75) we can find the slope as follows:
Slope is found via:

Plug in and calculate:

Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).


So our answer is:

To find y, we need to plug in 16 for x and solve:

First, use the points to find the equation of JK:
Given that JK passes through (4,5) and (144,75) we can find the slope as follows:
Slope is found via:
Plug in and calculate:
Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).
So our answer is:
To find y, we need to plug in 16 for x and solve:
Compare your answer with the correct one above
If
is defined as follows, is the point
on
?

If is defined as follows, is the point
on
?
To find out if (-2,5) is on f(x), simply plug the point into f(x)

Becomes,

So yes, it does!
To find out if (-2,5) is on f(x), simply plug the point into f(x)
Becomes,
So yes, it does!
Compare your answer with the correct one above
Which of the following are points along
if
.
Which of the following are points along if
.
One way to solve this one is by plugging in each of the answer choices and eliminating any that don't work out. Begin with our original g(x)

If we plug in 3 we get
,
So our point is (3,28).
One way to solve this one is by plugging in each of the answer choices and eliminating any that don't work out. Begin with our original g(x)
If we plug in 3 we get
,
So our point is (3,28).
Compare your answer with the correct one above
If
is defined as follows, is the point
on
?

If is defined as follows, is the point
on
?
To find out if (-2,5) is on f(x), simply plug the point into f(x)

Becomes,

So yes, it does!
To find out if (-2,5) is on f(x), simply plug the point into f(x)
Becomes,
So yes, it does!
Compare your answer with the correct one above
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug
into the
variable of the equation and solve for
:





To solve for for
, we have to plug
into the
variable of the equation and solve for
:
Compare your answer with the correct one above
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug 1 into the
variable of the equation and solve for
:






To solve for for
, we have to plug 1 into the
variable of the equation and solve for
:
Compare your answer with the correct one above
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug
into the
variable of the equation and solve for
:






To solve for for
, we have to plug
into the
variable of the equation and solve for
:
Compare your answer with the correct one above
Consider segment
which passes through the points
and
.
If the point
is on
, what is the value of y?
Consider segment which passes through the points
and
.
If the point is on
, what is the value of y?
First, use the points to find the equation of JK:
Given that JK passes through (4,5) and (144,75) we can find the slope as follows:
Slope is found via:

Plug in and calculate:

Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).


So our answer is:

To find y, we need to plug in 16 for x and solve:

First, use the points to find the equation of JK:
Given that JK passes through (4,5) and (144,75) we can find the slope as follows:
Slope is found via:
Plug in and calculate:
Next, we need to use one of our points and the slope to find our y-intercept. I'll use (4,5).
So our answer is:
To find y, we need to plug in 16 for x and solve:
Compare your answer with the correct one above
Which of the following are points along
if
.
Which of the following are points along if
.
One way to solve this one is by plugging in each of the answer choices and eliminating any that don't work out. Begin with our original g(x)

If we plug in 3 we get
,
So our point is (3,28).
One way to solve this one is by plugging in each of the answer choices and eliminating any that don't work out. Begin with our original g(x)
If we plug in 3 we get
,
So our point is (3,28).
Compare your answer with the correct one above
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug
into the
variable of the equation and solve for
:





To solve for for
, we have to plug
into the
variable of the equation and solve for
:
Compare your answer with the correct one above
Solve for
in the coordinate
on line
?
Solve for in the coordinate
on line
?
To solve for
for
, we have to plug 1 into the
variable of the equation and solve for
:






To solve for for
, we have to plug 1 into the
variable of the equation and solve for
:
Compare your answer with the correct one above