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GED Math · Question of the Day

GED Math Question of the Day

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Friday, September 18, 2026

A chemical solution's temperature, initially at T0T_0 degrees Celsius, decreases by kk degrees per minute for mm minutes. It is then rapidly heated, causing its temperature to increase by a total amount equal to one-fifth of its temperature after the cooling phase. Which expression represents the final temperature in degrees Celsius?

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A chemical solution's temperature, initially at T0T_0 degrees Celsius, decreases by kk degrees per minute for mm minutes. It is then rapidly heated, causing its temperature to increase by a total amount equal to one-fifth of its temperature after the cooling phase. Which expression represents the final temperature in degrees Celsius?

  1. T0−km+0.2T0T_0 - km + 0.2T_0
  2. 1.2(T0−km)1.2(T_0 - km) (correct answer)
  3. 1.2T0−km1.2T_0 - km
  4. T0−0.8kmT_0 - 0.8km

Explanation: Let's model the temperature changes step-by-step. The initial temperature is T0T_0. It decreases by kk degrees per minute for mm minutes, so the total decrease is kmkm. The temperature after the cooling phase is Tcooled=T0−kmT_{cooled} = T_0 - km. Next, the temperature increases by an amount equal to one-fifth (or 0.2) of this cooled temperature. The increase is 0.2×Tcooled=0.2(T0−km)0.2 \times T_{cooled} = 0.2(T_0 - km). The final temperature is the cooled temperature plus the increase: Tfinal=Tcooled+0.2×Tcooled=1×Tcooled+0.2×Tcooled=1.2×TcooledT_{final} = T_{cooled} + 0.2 \times T_{cooled} = 1 \times T_{cooled} + 0.2 \times T_{cooled} = 1.2 \times T_{cooled}. Substituting the expression for TcooledT_{cooled}, we get Tfinal=1.2(T0−km)T_{final} = 1.2(T_0 - km).