Multiplication - GED Math

Card 0 of 235

Multiply:

$263 \times 47$

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Multiply one digit at a time:

$\begin{matrix} 263\$\underline{ ; ; 47}$ \end{matrix}$

$\begin{matrix} ; ; 1841\ $\underline{1052}$; \end{matrix}$

The product is

Multiply:

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When multiplying numbers that have more than one digit, you follow the order below:

1. Multiply each digit in the first number () by the second digit in the second number (the in )

2. Add a in the units place under the in

3. Multiply each digit in the first number () by the first digit in the second number (the in ) and put the product on the same line as the .

3. Add and to get the answer.

Which of the following statements demonstrates the commutative property of multiplication?

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The commutative property of multiplication states that two numbers can be multiplied in either order to yield the same product. Of the four choices,

$\frac{1}{2}$ \times $\frac{1}{3}$ = $\frac{1}{3}$ \times $\frac{1}{2}$

demonstrates this. It is the correct choice.

Which statement demonstrates the associatve property of multiplication?

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The associative property of multiplication states that when three numbers are multiplied, any two can be multiplied first and the same product will appear. Of the four choices,

$\frac{9}{10}$ \times\left ( $\frac{10}{11}$ \times $\frac{11}{12}$ \right )= \left ($\frac{9}{10}$ \times $\frac{10}{11}$ \right )\times $\frac{11}{12}$

demonstrates this.

What property of arithmetic is symbolized below?

$\bigstar \times \blacksquare = \blacksquare \times \bigstar$

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The symbols show that two numbers can be multiplied in either order to achieve the same result. This is the commutative property of multiplication.

Above is the menu for a coffee shop; there is no sales tax charged on purchases.

Myoshi wants to throw an informal party. She wants to serve one large cafe latte and two butter croissants to each guest, and she wants to keep expenses at or below $200. Counting herself, how many people, at most, will be at the party?

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Since one large cafe latte and two butter croissants will cost

,

this will be the amount Myoshi spends per person. She wants to spend at most $200, so, letting stand for the number of people at the party, we can set up and solve this inequality:

$8.57x \leq 200$

$8.57x \div 8.57 \leq 200 \div 8.57$

$x \leq 23.3$

There can be at most 23 people at Myoshi's party.

Multiply the numbers: $54\times 89$

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Multiply the first number with the ones digit of the second number.

$54\times 9=486$

Multiply 54 with the tens digit of the second number.

$54\times 8 = 432$

Add a zero to the end of this number and add this number with the first number.

The answer is:

Multiply the numbers: $23 \times 15$

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Multiply the first number with the ones digit of 15.

$23\times 5 = 115$

Repeat the process with the tens digit of 15.

$23\times 1 = 23$

Add a zero to the end of this number and add this number with the first number.

The answer is:

Multiply the numbers: $26\times 32$

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Multiply 26 with the ones digit of the second number.

$26\times 2 = 52$

Multiply 26 with the tens digit of the second number.

$26\times 3 = 78$

Add an extra zero to the end of this number and add this value with the first number.

The answer is:

Multiply the following numbers: $54\times 78$

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Multiply the first number with the ones digit of the second number.

$54\times 8 = 432$

Repeat the process with the tens digit of the second number.

$54\times 7 = 378$

Add a zero to the end of this number and add this with the first number.

The answer is:

Multiply the following numbers: $314\times 15$

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Multiply the first number with the ones digit of 15.

$314\times 5 = 1570$

Multiply the first number with the tens digit of 15.

$314\times 1 = 314$

Add a zero to the end of this number and add this with the first number solved.

The answer is:

Multiply the following:

$\frac{1}{6}$ \cdot $\frac{1}{2}$

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To multiply fractions, we will multiply the numerators together, then we will multiply the denominators together.

So, we get

$\frac{1}{6}$ \cdot $\frac{1}{2}$

$\frac{1 \cdot 1}{6 \cdot 2}$

$\frac{1}{12}$

Multiply the numbers: $72\times 76$

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Multiply the first number with the ones digit of the second number.

$72\times 6 = 432$

Multiply the first number with the tens digit of the second number.

$72\times 7 = 504$

Add a zero to the end of this number and add this with the first number calculated.

The answer is:

Multiply the following numbers: $32\times 87$

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Multiply the first number with the ones digit of the second number.

$32\times 7 = 224$

Repeat the process with the tens digit.

$32\times 8= 256$

Add a zero to the end of this number and add it with the first number solved.

The answer is:

Multiply the numbers: $61\times 24$

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Multiply the first number with the ones digit of the second number.

$61\times 4 = 244$

Repeat using the tens digit of the second number.

$61\times 2 = 122$

Add a zero to the end of this number and add this with the first number.

The answer is:

Multiply the following numbers: $15\times 23$

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Multiply the first number with the ones digit of the second number.

$15\times 3 = 45$

Repeat the process with the tens digit.

$15\times 2 = 30$

Add an extra zero to the end of this number and add the number with the first number calculated.

The answer is:

Multiply the numbers: $98\times 45$

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Multiply the first number with the ones digit of the second number.

$98\times 5 = 490$

Multiply the first number with the tens digit of the second number.

$98\times 4 = 392$

Add a zero to the end of this number and add this value to the first number.

The answer is:

Multiply the numbers: $78\times 54$

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Multiply the first number with the ones digit of the second number.

$78\times 4 = 312$

Multiply the first number with the tens digit of the second number.

$78\times 5 = 390$

Add a zero to the end of this number and add the value with the first number.

The answer is:

Multiply the numbers: $516\times18$

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Multiply the first number with the ones digit of the second number.

$516\times 8 = 4128$

Multiply the first number with the tens digit of the second number.

$516\times 1 = 516$

Add a zero to the end of this number and all the first number.

The answer is:

Multiply the numbers: $49\times 24$

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Multiply 49 with the ones digit of the second number.

$49\times 4 = 196$

Multiply 49 with the tens digit of the second number.

$49\times 2 = 98$

Add a zero to the end of this number and add it with the first number.

The answer is: