Whole Numbers - Basic Math
Card 0 of 180
Solve for
.

Solve for .
First, add 6 to both sides so that the term with "x" is on its own.

Now, divide both sides by 2.

First, add 6 to both sides so that the term with "x" is on its own.
Now, divide both sides by 2.
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Solve:

Solve:
The answer is
. The goal is to isolate the variable,
, on one side of the equation sign and have all numerical values on the other side of the equation.
Since
is a negative number, you must add
to both sides.

Then, divide both sides of the equation by
:

The answer is . The goal is to isolate the variable,
, on one side of the equation sign and have all numerical values on the other side of the equation.
Since is a negative number, you must add
to both sides.
Then, divide both sides of the equation by :
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Solve for
.

Solve for .
Start by isolating the term with
to one side. Add 10 on both sides.

Divide both sides by 7.

Start by isolating the term with to one side. Add 10 on both sides.
Divide both sides by 7.
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If
, what is
equal to?
If , what is
equal to?
When solving an equation, we need to find a value of x which makes each side equal each other. We need to remember that
is equal to and the same as
. When we solve an equation, if we make a change on one side, we therefore need to make the exact same change on the other side, so that the equation stays equal and true. To illustrate, let's take a numerical equation:

If we subtract
from each side, the equation still remains equal:


If we now divide each side by
, the equation still remains equal:


This still holds true even if we have variables in our equation. We can perform the inverse operations to isolate the variable on one side and find out what number it's equal to. To solve our problem then, we need to isolate our
term. We can do that by subtracting
from each side, the inverse operation of adding
:


We now want there to be one
on the left side.
is the same thing as
, so we can get rid of the 6 by performing the inverse operation on both sides, i.e. dividing each side by
:

is therefore our final answer.
When solving an equation, we need to find a value of x which makes each side equal each other. We need to remember that is equal to and the same as
. When we solve an equation, if we make a change on one side, we therefore need to make the exact same change on the other side, so that the equation stays equal and true. To illustrate, let's take a numerical equation:
If we subtract from each side, the equation still remains equal:
If we now divide each side by , the equation still remains equal:
This still holds true even if we have variables in our equation. We can perform the inverse operations to isolate the variable on one side and find out what number it's equal to. To solve our problem then, we need to isolate our term. We can do that by subtracting
from each side, the inverse operation of adding
:
We now want there to be one on the left side.
is the same thing as
, so we can get rid of the 6 by performing the inverse operation on both sides, i.e. dividing each side by
:
is therefore our final answer.
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Solve for
.

Solve for .
Start by adding 10 to both sides of the equation.

Then, divide both sides by
.

Start by adding 10 to both sides of the equation.
Then, divide both sides by .
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Solve for t.

Solve for t.
First start by distributing the 7.


Now, add both sides by 14.

Finally, divide both sides by 7.

First start by distributing the 7.
Now, add both sides by 14.
Finally, divide both sides by 7.
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Solve for
:

Solve for :
First, add
to both sides of the equation:

Then, divide both sides by
:

First, add to both sides of the equation:
Then, divide both sides by :
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For the following questions, please select the answer that most correctly completes the equation.

For the following questions, please select the answer that most correctly completes the equation.

Ones digit: 
Tens digit:
(leave the two at the tens, carry the one to the hundreds digit)
Hundreds digit:
, add the one from the tens digit, so you get 5 + 1 = 6
Thousands digit: 
Ones digit:
Tens digit: (leave the two at the tens, carry the one to the hundreds digit)
Hundreds digit: , add the one from the tens digit, so you get 5 + 1 = 6
Thousands digit:
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Find the sum.

Find the sum.
First add the digits in the ones colume, this would be
. Make sure to carry the 1 from the 17 to the tens colume.
Then add the digits in the tens colume, this would be
.
Lastly, add the digits in the hundrends colume, this would be 
Therefore the result is as follows:

First add the digits in the ones colume, this would be . Make sure to carry the 1 from the 17 to the tens colume.
Then add the digits in the tens colume, this would be .
Lastly, add the digits in the hundrends colume, this would be
Therefore the result is as follows:
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If I had
in the bank and deposited an additonal
today, how much do I have in total?
If I had in the bank and deposited an additonal
today, how much do I have in total?
1. Add the ones places:

2. Add the tens places:

***don't forget to put the 3 down and carry the one to the hundreds place***
3. Add the hundreds place:

This makes your total:

1. Add the ones places:
2. Add the tens places:
***don't forget to put the 3 down and carry the one to the hundreds place***
3. Add the hundreds place:
This makes your total:
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What is the solution of the above operation?
What is the solution of the above operation?

We can see this because if we had 5 (represented by
) and add another 2 objects (represented by
) we should get 7 objects (
and
) total.

We have 7 objects total!
We can see this because if we had 5 (represented by ) and add another 2 objects (represented by
) we should get 7 objects (
and
) total.
We have 7 objects total!
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What is the solution of the above equation?
What is the solution of the above equation?

If x represents objects.
For 5:

For 6:


We can see that 11 objects result.
If x represents objects.
For 5:
For 6:
We can see that 11 objects result.
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Paul had
video games. On Monday, he gave
video games to his friend Chris. On Tuesday, he sold
of his video games to the local video game shop. On Wednesday, Paul accidentally broke
video games and threw them away. How many video games does Paul have left?
Paul had video games. On Monday, he gave
video games to his friend Chris. On Tuesday, he sold
of his video games to the local video game shop. On Wednesday, Paul accidentally broke
video games and threw them away. How many video games does Paul have left?
This is a simple subtraction problem.
First, subtract the number of video games Paul gave to Chris on Monday.

Now, subtract the number of video games Paul sold from the number he has left.

Finally, subtract the number of video games Paul broke and threw away.

This is a simple subtraction problem.
First, subtract the number of video games Paul gave to Chris on Monday.
Now, subtract the number of video games Paul sold from the number he has left.
Finally, subtract the number of video games Paul broke and threw away.
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What is the solution of the above equation?
What is the solution of the above equation?

We can show this using objects:



We can see that only 7 objects are left.
We can show this using objects:
We can see that only 7 objects are left.
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What is the solution of the above equation?
What is the solution of the above equation?

We can see that by the objects.



We can see that there is only one object left.
We can see that by the objects.
We can see that there is only one object left.
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Timmy has
sea monkeys. At the end of the first month that he has them,
sea monkeys die, and his parents buy him
new ones. At the end of the second month,
more sea monkeys die. How many sea monkeys does Timmy have at the end of the second month?
Timmy has sea monkeys. At the end of the first month that he has them,
sea monkeys die, and his parents buy him
new ones. At the end of the second month,
more sea monkeys die. How many sea monkeys does Timmy have at the end of the second month?
The problem can be solved as follows. First, calculate the number of sea monkeys left at the end of the first month:

Then, calculate the number of sea monkeys left at the end of the second month:

The problem can be solved as follows. First, calculate the number of sea monkeys left at the end of the first month:
Then, calculate the number of sea monkeys left at the end of the second month:
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Solve for
:

Solve for :
To solve for n we need to isolate n on one side of the equation and all of the constants on the other side.

We do this by adding 15 to both sides.

Then we add 12 to both sides to get our final answer.

To solve for n we need to isolate n on one side of the equation and all of the constants on the other side.
We do this by adding 15 to both sides.
Then we add 12 to both sides to get our final answer.
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What is
?
What is ?

If you need to break it down, you can split it into smaller pieces:
and
, and then add the pieces back together:
.
If you need to break it down, you can split it into smaller pieces:
and
, and then add the pieces back together:
.
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A city bus has five stops left on its route. At the first stop,
people get off. At the second stop,
get off. At the third, no one gets off. At the fourth,
people get off. At the fifth, there are
people left on the bus, and they all get off. How many people were on the bus before the first stop?
A city bus has five stops left on its route. At the first stop, people get off. At the second stop,
get off. At the third, no one gets off. At the fourth,
people get off. At the fifth, there are
people left on the bus, and they all get off. How many people were on the bus before the first stop?
To solve, create a linear equation:
represents the total number of people on the bus before the first stop.
We then subtract the amount of people that got off at each stop and set that equal to the number of people to get off at the final stop.



To solve, create a linear equation:
represents the total number of people on the bus before the first stop.
We then subtract the amount of people that got off at each stop and set that equal to the number of people to get off at the final stop.
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For the following questions, please select the answer that most correctly completes the equation.

For the following questions, please select the answer that most correctly completes the equation.

Ones digit: 
Tens digit:
(leave the two at the tens, carry the one to the hundreds digit)
Hundreds digit:
, add the one from the tens digit, so you get 5 + 1 = 6
Thousands digit: 
Ones digit:
Tens digit: (leave the two at the tens, carry the one to the hundreds digit)
Hundreds digit: , add the one from the tens digit, so you get 5 + 1 = 6
Thousands digit:
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