Images Formed by Lenses - AP Physics 2
Card 1 of 30
Define focal length for a lens.
Define focal length for a lens.
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Distance from lens center to focal point. Where parallel rays converge or appear to diverge.
Distance from lens center to focal point. Where parallel rays converge or appear to diverge.
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Which lens type converges light rays?
Which lens type converges light rays?
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Convex lens. Brings parallel rays together at focal point.
Convex lens. Brings parallel rays together at focal point.
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Identify the nature of the image formed by a concave lens.
Identify the nature of the image formed by a concave lens.
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Virtual, upright, and reduced. Concave lenses always diverge light, creating virtual images.
Virtual, upright, and reduced. Concave lenses always diverge light, creating virtual images.
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Calculate magnification if $d_o = 10$ cm and $d_i = -5$ cm.
Calculate magnification if $d_o = 10$ cm and $d_i = -5$ cm.
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$m = 0.5$. Magnification equals negative ratio: $m = -\frac{(-5)}{10} = 0.5$
$m = 0.5$. Magnification equals negative ratio: $m = -\frac{(-5)}{10} = 0.5$
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What type of image is formed at 2F by a convex lens?
What type of image is formed at 2F by a convex lens?
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Real, inverted, and same size. Object at twice focal length creates unit magnification.
Real, inverted, and same size. Object at twice focal length creates unit magnification.
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Determine the magnification for $d_o = 25$ cm and $d_i = 50$ cm.
Determine the magnification for $d_o = 25$ cm and $d_i = 50$ cm.
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$m = -2$. Magnification equals negative distance ratio: $m = -\frac{50}{25}$
$m = -2$. Magnification equals negative distance ratio: $m = -\frac{50}{25}$
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Determine the power of a lens with focal length $-0.5$ m.
Determine the power of a lens with focal length $-0.5$ m.
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$P = -2$ D. Negative power indicates diverging lens: $P = \frac{1}{-0.5}$
$P = -2$ D. Negative power indicates diverging lens: $P = \frac{1}{-0.5}$
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Identify the image when an object is placed at infinity for a convex lens.
Identify the image when an object is placed at infinity for a convex lens.
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Real, inverted, and at F. Parallel rays from infinity converge at focal point.
Real, inverted, and at F. Parallel rays from infinity converge at focal point.
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What is the unit of power for lenses?
What is the unit of power for lenses?
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Diopter (D). Standard unit for measuring lens refractive power.
Diopter (D). Standard unit for measuring lens refractive power.
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Identify the type of image formed by a convex lens when object is beyond 2F.
Identify the type of image formed by a convex lens when object is beyond 2F.
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Real, inverted, and reduced. Object farther than twice the focal length produces these characteristics.
Real, inverted, and reduced. Object farther than twice the focal length produces these characteristics.
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Which lens type converges light rays?
Which lens type converges light rays?
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Convex lens. Brings parallel rays together at focal point.
Convex lens. Brings parallel rays together at focal point.
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Identify the image characteristics when object is between F and 2F of a convex lens.
Identify the image characteristics when object is between F and 2F of a convex lens.
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Real, inverted, and magnified. Object between focal points creates enlarged real image.
Real, inverted, and magnified. Object between focal points creates enlarged real image.
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Find the image distance if $f = 10$ cm and $d_o = 15$ cm for a convex lens.
Find the image distance if $f = 10$ cm and $d_o = 15$ cm for a convex lens.
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$d_i = 30$ cm. Using lens formula: $\frac{1}{10} = \frac{1}{15} + \frac{1}{d_i}$
$d_i = 30$ cm. Using lens formula: $\frac{1}{10} = \frac{1}{15} + \frac{1}{d_i}$
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What does a negative magnification value indicate?
What does a negative magnification value indicate?
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Image is inverted. Negative magnification means image is flipped vertically.
Image is inverted. Negative magnification means image is flipped vertically.
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What type of image is formed by a lens if the object is placed between the lens and the focal point?
What type of image is formed by a lens if the object is placed between the lens and the focal point?
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Virtual and magnified. Object inside focal length produces enlarged virtual image.
Virtual and magnified. Object inside focal length produces enlarged virtual image.
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Describe the image when an object is at the focal point of a convex lens.
Describe the image when an object is at the focal point of a convex lens.
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No image is formed. Parallel rays emerge, creating no convergence point.
No image is formed. Parallel rays emerge, creating no convergence point.
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Which type of lens corrects hyperopia?
Which type of lens corrects hyperopia?
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Convex lens. Converging lens focuses light to correct farsightedness.
Convex lens. Converging lens focuses light to correct farsightedness.
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Which type of lens corrects myopia?
Which type of lens corrects myopia?
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Concave lens. Diverging lens spreads light to correct nearsightedness.
Concave lens. Diverging lens spreads light to correct nearsightedness.
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Determine the power of a lens with focal length $-0.5$ m.
Determine the power of a lens with focal length $-0.5$ m.
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$P = -2$ D. Negative power indicates diverging lens: $P = \frac{1}{-0.5}$
$P = -2$ D. Negative power indicates diverging lens: $P = \frac{1}{-0.5}$
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Find the focal length if power of lens is $+5$ D.
Find the focal length if power of lens is $+5$ D.
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$f = 0.2$ m. Power equals reciprocal of focal length: $f = \frac{1}{5}$
$f = 0.2$ m. Power equals reciprocal of focal length: $f = \frac{1}{5}$
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Determine the magnification for $d_o = 25$ cm and $d_i = 50$ cm.
Determine the magnification for $d_o = 25$ cm and $d_i = 50$ cm.
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$m = -2$. Magnification equals negative distance ratio: $m = -\frac{50}{25}$
$m = -2$. Magnification equals negative distance ratio: $m = -\frac{50}{25}$
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What type of image is formed at 2F by a convex lens?
What type of image is formed at 2F by a convex lens?
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Real, inverted, and same size. Object at twice focal length creates unit magnification.
Real, inverted, and same size. Object at twice focal length creates unit magnification.
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Calculate magnification if $d_o = 10$ cm and $d_i = -5$ cm.
Calculate magnification if $d_o = 10$ cm and $d_i = -5$ cm.
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$m = 0.5$. Magnification equals negative ratio: $m = -\frac{(-5)}{10} = 0.5$
$m = 0.5$. Magnification equals negative ratio: $m = -\frac{(-5)}{10} = 0.5$
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Identify the nature of the image formed by a concave lens.
Identify the nature of the image formed by a concave lens.
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Virtual, upright, and reduced. Concave lenses always diverge light, creating virtual images.
Virtual, upright, and reduced. Concave lenses always diverge light, creating virtual images.
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What is the magnification formula for lenses?
What is the magnification formula for lenses?
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Magnification $m = \frac{h_i}{h_o} = -\frac{d_i}{d_o}$. Ratio of image to object height equals negative distance ratio.
Magnification $m = \frac{h_i}{h_o} = -\frac{d_i}{d_o}$. Ratio of image to object height equals negative distance ratio.
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State the effect of lens curvature on focal length.
State the effect of lens curvature on focal length.
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More curvature, shorter focal length. Greater curvature increases light bending, reducing focal length.
More curvature, shorter focal length. Greater curvature increases light bending, reducing focal length.
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What is the nature of the image formed when an object is placed at 2F of a concave lens?
What is the nature of the image formed when an object is placed at 2F of a concave lens?
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Virtual, upright, and reduced. Concave lenses always produce diminished virtual images.
Virtual, upright, and reduced. Concave lenses always produce diminished virtual images.
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When is an image formed by a lens virtual?
When is an image formed by a lens virtual?
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When image distance $d_i$ is negative. Negative $d_i$ means image forms on same side as object.
When image distance $d_i$ is negative. Negative $d_i$ means image forms on same side as object.
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How does image distance relate to object distance for a real image in a lens?
How does image distance relate to object distance for a real image in a lens?
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Image distance $d_i$ is positive. Real images form on opposite side of lens from object.
Image distance $d_i$ is positive. Real images form on opposite side of lens from object.
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Find the image distance if $f = 12$ cm and $d_o = 24$ cm for a convex lens.
Find the image distance if $f = 12$ cm and $d_o = 24$ cm for a convex lens.
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$d_i = 24$ cm. Using lens formula: $\frac{1}{12} = \frac{1}{24} + \frac{1}{d_i}$
$d_i = 24$ cm. Using lens formula: $\frac{1}{12} = \frac{1}{24} + \frac{1}{d_i}$
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