Introduction to Entropy
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AP Chemistry › Introduction to Entropy
At 1 atm, liquid nitrogen, N$_2$(l), warms and boils to form N$_2$(g) in an open container. Considering the nitrogen as the system during boiling (liquid to gas), does entropy increase, decrease, or remain approximately constant?
Entropy remains approximately constant because nitrogen remains N$_2$.
Entropy increases because gas particles are more dispersed than liquid particles.
Entropy decreases because boiling requires energy input.
Entropy decreases because the temperature increases during warming.
Entropy remains approximately constant because the pressure is constant at 1 atm.
Explanation
This question tests entropy during boiling at constant pressure. Boiling N₂(l) to N₂(g) disperses molecules from liquid to gas, increasing entropy due to greater freedom. The open container and 1 atm facilitate the phase change. Warming does not decrease entropy here. A tempting distractor is choice B, which claims entropy remains constant because it's still N₂, but this misconceives that unchanged formula prevents entropy changes, disregarding phase differences. In boiling, highlight the entropy gain from gaseous expansion.
A student opens a container of perfume in a corner of a room. Over time, the perfume molecules spread throughout the room air. Considering the perfume molecules as the system, does entropy increase, decrease, or remain approximately constant?
Entropy remains approximately constant because the temperature of the room is constant.
Entropy increases because the molecules become more dispersed throughout the room.
Entropy decreases because the perfume concentration decreases.
Entropy remains approximately constant because no new substances form.
Entropy decreases because diffusion is exothermic.
Explanation
This question assesses entropy changes due to diffusion of molecules in a gas phase. Opening the perfume container allows its molecules to spread from a concentrated area to disperse throughout the room air, increasing their randomness and accessible microstates. This diffusion process results in an entropy increase for the perfume molecules as the system. The room's constant temperature supports the spontaneous nature of this dispersal. A tempting distractor is choice C, which suggests entropy remains constant because room temperature is constant, but this misconceives that isothermal conditions prevent entropy increases, overlooking diffusion's role in enhancing disorder. In diffusion scenarios, think about how spreading molecules over larger volumes inherently increases entropy.
A sealed flask contains a mixture of N$_2$(g) and O$_2$(g) separated by a removable partition, both gases at the same temperature and pressure. The partition is removed and the gases mix uniformly. For the gases (the system), does entropy increase, decrease, or remain approximately constant?
Entropy decreases because the process is not a chemical reaction.
Entropy remains approximately constant because N$_2$ and O$_2$ are both diatomic.
Entropy decreases because mixing reduces the partial pressure of each gas.
Entropy increases because mixing increases the number of accessible microstates.
Entropy remains approximately constant because total pressure is unchanged.
Explanation
This question probes entropy changes upon mixing ideal gases. Removing the partition allows N₂ and O₂ to mix uniformly, increasing the dispersal of each gas throughout the entire volume and creating more possible arrangements. This mixing process, known as entropy of mixing, results in an overall entropy increase for the system at constant temperature and pressure. The gases do not react, so the change is purely physical. A tempting distractor is choice A, which claims entropy remains constant because total pressure is unchanged, but this misconceives that constant total pressure implies no entropy change, disregarding the role of mixing in increasing disorder. For gas mixing, consider how combining components increases configurational entropy through greater particle arrangements.
At 1 atm, a sample of ethanol is cooled from 25°C to its freezing point and then frozen to form solid ethanol. Considering only the phase change from liquid to solid for the system, does entropy increase, decrease, or remain approximately constant?
Entropy increases because freezing releases heat to the surroundings.
Entropy remains approximately constant because pressure is constant.
Entropy decreases because particles become more ordered in the solid.
Entropy increases because the temperature decreases.
Entropy remains approximately constant because the chemical formula does not change.
Explanation
This question examines entropy variations during freezing, a liquid-to-solid phase change. Cooling ethanol to its freezing point and solidifying it organizes the molecules into a rigid crystal lattice, reducing their freedom of motion and dispersal. This transition to a more ordered state decreases the entropy of the system. The constant pressure of 1 atm does not alter the fundamental entropy decrease associated with freezing. A tempting distractor is choice C, which suggests entropy remains constant because the chemical formula is unchanged, but this misconceives that phase changes do not affect entropy, ignoring the order difference between liquids and solids. When analyzing phase changes, compare the molecular disorder in the initial and final states to determine entropy direction.
At constant pressure, a sample of liquid ethanol is heated until it boils and becomes ethanol vapor. Considering only the ethanol (system), how does entropy change during vaporization?
Entropy decreases because intermolecular forces are overcome and particles separate.
Entropy decreases because boiling requires energy input, which creates order.
Entropy increases because the particles move more freely in the gas phase than in the liquid phase.
Entropy remains approximately constant because the pressure is held constant throughout.
Entropy remains approximately constant because the temperature stays at the boiling point during the phase change.
Explanation
This question tests the understanding of entropy changes during vaporization at constant pressure. The stimulus describes liquid ethanol being heated to boil and become vapor, transitioning from liquid to gas phase. Entropy increases because in the gas phase, ethanol molecules have greater freedom of motion, higher kinetic energy, and more accessible microstates than in the more constrained liquid phase. This is supported by the positive ΔS_vap values for substances, reflecting the disorder increase upon overcoming intermolecular forces. A tempting distractor is choice C, which incorrectly claims entropy remains constant because temperature is constant at the boiling point, misconstruing isothermal conditions with no change in microstates and ignoring the phase transition's effect. For entropy evaluations in phase changes, assess how breaking intermolecular interactions allows for greater particle independence in the vapor phase.
A small crystal of KBr(s) is added to a large beaker of water at 25°C and dissolves completely to form K$^+$(aq) and Br$^-$(aq). Considering the system as the solute particles and water in the beaker, what is the best qualitative statement about $\Delta S$ for the dissolving process?
$\Delta S$ decreases because ions in solution are more ordered than a crystal.
$\Delta S$ remains approximately constant because the mass of solute is unchanged.
$\Delta S$ decreases because dissolving must absorb heat to break the lattice.
$\Delta S$ increases because the ions disperse throughout the solvent.
$\Delta S$ increases because the temperature of the solution increases.
Explanation
This question tests understanding of entropy changes during ionic dissolution. When crystalline KBr dissolves, the K+ and Br- ions transition from fixed positions in a highly ordered crystal lattice to freely moving hydrated ions dispersed throughout the solution. This dramatic increase in the freedom of movement and the number of possible arrangements for both the ions and the water molecules that hydrate them results in a positive ΔS. A common misconception is that ΔS decreases because ions in solution are more ordered than in a crystal (choice A), but the opposite is true - dissolved ions have much more freedom than those in a crystal lattice. For ionic dissolution, entropy typically increases due to increased particle dispersal.
Dry ice (solid CO$_2$) at $-78,^{\circ}\mathrm{C}$ is placed in an open container and sublimates completely into CO$_2$(g) at the same temperature. Considering only the CO$_2$ sample, does the entropy increase, decrease, or remain approximately constant?
The entropy remains approximately constant because the temperature stays at $-78,^{\circ}\mathrm{C}$.
The entropy decreases because the CO$_2$ absorbs heat from the surroundings.
The entropy decreases because the solid CO$_2$ is denser than the gas.
The entropy remains approximately constant because the chemical identity of CO$_2$ does not change.
The entropy increases because a gas has more accessible microstates than a solid.
Explanation
This question tests the understanding of entropy changes in sublimation from solid to gas. As solid CO2 sublimes into gas at constant temperature, the molecules move from a highly ordered lattice to a dispersed gaseous state. This phase change significantly increases the number of accessible microstates due to greater positional freedom. The process is endothermic, but entropy is governed by the increase in disorder. A tempting distractor is choice A, which claims entropy remains constant because temperature is constant, but this misconception disregards the profound impact of phase transitions on microstates. When assessing sublimation or deposition, focus on the entropy increase associated with transitioning to less constrained phases like gases.
A saturated solution of KNO$_3$(aq) at 60°C is slowly cooled to 25°C, and solid KNO$_3$(s) crystallizes out while the remaining solution stays at 25°C. Consider the KNO$_3$ (both dissolved and solid) as the system. Does the entropy increase, decrease, or remain approximately constant during crystallization?
The entropy remains approximately constant because the total amount of KNO$_3$ in the beaker is unchanged.
The entropy decreases because forming an ordered crystal reduces the number of accessible microstates.
The entropy increases because cooling always increases entropy by lowering kinetic energy.
The entropy remains approximately constant because crystallization is a physical change, not a chemical reaction.
The entropy increases because the solution becomes less concentrated as solid forms.
Explanation
This question tests the understanding of entropy changes during crystallization from solution. Cooling the saturated KNO3 solution causes dissolved ions to form an ordered solid crystal, reducing the dispersion of KNO3 particles. This transition to a more structured state decreases the number of accessible microstates, lowering entropy. The remaining solution is less concentrated, but the ordering in the solid dominates. A tempting distractor is choice D, which claims entropy increases due to lower concentration, but this misconception overlooks the entropy decrease from forming an ordered solid. In crystallization processes, evaluate entropy by comparing the disorder in solution versus the order in the crystalline product.
At 25°C, 50.0 mL of 1.0 M NaCl(aq) is poured into 50.0 mL of pure water in an open beaker and stirred until uniform. Assume no significant temperature change. For the solution (system), does the entropy increase, decrease, or remain approximately constant?
The entropy remains approximately constant because the temperature does not change appreciably.
The entropy decreases because dissolving ions creates strong ion–dipole attractions that make the system more ordered.
The entropy increases because mixing produces a more dispersed distribution of solute particles.
The entropy remains approximately constant because the total volume doubles.
The entropy decreases because the concentration of NaCl decreases upon dilution.
Explanation
This question tests the concept of entropy changes upon mixing or dilution of solutions. Pouring 1.0 M NaCl into pure water doubles the volume, dispersing the NaCl ions more widely and creating a more uniform mixture. This increased dispersion enhances the number of possible arrangements of solute particles, increasing the entropy of the system. The temperature remains constant, but the mixing effect drives the entropy change. A tempting distractor is choice A, which suggests entropy decreases due to ion-dipole attractions creating order, but this misconception overemphasizes interactions while ignoring the overall increase in dispersion. To analyze entropy in solutions, consider how dilution or mixing promotes greater particle distribution and randomness.
A piece of copper metal at 25°C is heated to 80°C on a hot plate, remaining solid the entire time. Consider the copper as the system. Does the entropy increase, decrease, or remain approximately constant?
The entropy remains approximately constant because the hot plate provides heat at constant pressure.
The entropy decreases because heating increases order in a solid lattice.
The entropy remains approximately constant because the phase does not change.
The entropy decreases because copper has a fixed composition and fixed molar mass.
The entropy increases because increasing temperature increases the number of accessible vibrational microstates.
Explanation
This question tests the concept of entropy changes with temperature in solids. Heating copper from 25°C to 80°C increases atomic vibrational energy, expanding accessible microstates. This temperature rise enhances entropy without phase change. The solid remains structured, but thermal motion increases disorder. A tempting distractor is choice C, which suggests entropy remains constant because no phase change occurs, but this misconception ignores temperature's role in vibrational entropy. When heating materials, recognize that higher temperatures generally increase entropy through greater energy distribution.