This is a prediction question requiring you to apply learned principles to new scenarios. The introduction established that "S-waves... travel only through solids." Therefore, if a layer contains liquid (magma), S-waves cannot travel through it, meaning velocity must be 0 km/s. This is exactly what happens in the Outer Core (liquid) where S-wave velocity is 0. Choice B correctly applies this principle. Choice A (spike) contradicts the inability to travel through liquids. Choice C (remain unchanged) ignores the liquid's effect. Choice D (equal to P-wave) is wrong because P-waves CAN travel through liquids. Pro tip: Apply established rules from the introduction to new hypothetical situations.

The correct answer is C. Table 1 establishes the relationship between voltage and current: as voltage increases from 2.0 to 10.0 V, current increases proportionally from 0.20 to 1.00 A. When one quantity increases and the other increases in proportion, they are directly proportional. Table 2 establishes the relationship between resistance and current: as resistance increases from 2.0 to 12.0 Ω, current decreases from 6.00 to 1.00 A. When one quantity increases and the other decreases, they are inversely proportional. C correctly identifies both relationships: current is directly proportional to voltage (Table 1) and inversely proportional to resistance (Table 2). A is wrong — current is not directly proportional to resistance; Table 2 shows the opposite. B is wrong — current is not inversely proportional to voltage; Table 1 shows direct proportionality. D reverses both relationships. This question synthesizes findings from two separate tables to derive Ohm's Law (I = V/R) from the experimental data alone.

The correct answer is C (between 28% and 54%). Study 1's data shows that at 80 mM/kg NaCl, the germination rate was 54%, and at 120 mM/kg NaCl, it was 28%. A concentration of 100 mM/kg falls between these two tested values, so the germination rate must fall between their corresponding outcomes: between 28% and 54%. F (greater than 82%) would require a lower NaCl concentration than 40 mM/kg. G (between 54% and 82%) corresponds to concentrations between 40 and 80 mM/kg — too low. H correctly identifies the range between 80 and 120 mM/kg. D (less than 28%) would require a concentration above 120 mM/kg. On interpolation questions, identify the two tested values that bracket the given value and read their corresponding outcomes.

The correct answer is C. Star D has a surface temperature of 6,000 K and a luminosity of 1 L☉. Twice as hot as Star D is 12,000 K. On the Main Sequence of the H-R diagram, following the diagonal band from 6,000 K (luminosity ~1) to 12,000 K, the luminosity value on the logarithmic y-axis rises to approximately 10² — meaning roughly 100 times the Sun's luminosity. Therefore the luminosity increases by a factor between 10 and 100. A and B (half or twice) dramatically underestimate the increase — the Main Sequence's trend on a log scale shows a much steeper relationship than a simple doubling. D (10⁵ to 10⁶ times greater) dramatically overestimates — these luminosities correspond to the Supergiant region, far above the Main Sequence at 12,000 K. This question tests the ability to read the nonlinear (logarithmic) trend of the Main Sequence rather than applying simple arithmetic. Pro tip: on log-scale diagrams, a visual shift of one unit on the y-axis represents a tenfold change in the actual quantity.

The correct answer is C (quadruples). Check the data systematically: when x = 2.0 cm, D = 5.0 m. When x doubles to 4.0 cm, D = 20.0 m — that is 4 × 5.0 = 20.0, a factor of 4 increase. Confirm with the next doubling: when x doubles from 4.0 cm to 8.0 cm, D goes from 20.0 m to 80.0 m — that is 4 × 20.0 = 80.0, again a factor of 4. The relationship is quadratic: D is proportional to x². This makes physical sense — the energy stored in a compressed spring is proportional to x², and if energy converts directly to kinetic energy, the velocity and ultimately the distance scale with x². A (stays the same) would require constant D regardless of x. B (doubles) would give D = 10.0 at x = 4.0, but the table shows 20.0. D (increases by exactly 15.0) would give inconsistent additions. On relationship questions, always test the proposed relationship against at least two data pairs before confirming.

The correct answer is D (Star D). The passage's introduction defines the luminosity scale: 'Luminosity is a measure of a star's total energy output compared to the Sun (L☉).' By definition, the Sun itself has a luminosity of exactly 1 L☉ — this is the reference point of the scale. Table 1 shows that Star D has a luminosity of 1 L☉ and a surface temperature of 6,000 K. A surface temperature of approximately 5,500–6,000 K is consistent with the Sun's known surface temperature, and a luminosity of exactly 1 L☉ is the defining property of the Sun. Star A (luminosity 10⁴) is far too bright. Star B (luminosity 10⁵) is even brighter. Star C (luminosity 10⁻³) is far too dim. This question tests whether students recognize that the unit L☉ is defined relative to the Sun, making 1 L☉ the Sun's own luminosity by definition.

The correct answer is B. The introduction — which establishes shared scientific facts before the viewpoints diverge — states: 'Geologists have discovered a distinct layer of sedimentary rock worldwide at the K-Pg boundary that contains unusually high levels of iridium.' Both scientists accept this fact; they disagree only about the source of that iridium (asteroid vs. deep mantle). A is wrong — neither scientist specifies a ten-year formation period; Scientist 2 describes processes lasting tens of thousands of years. C is directly contradicted by both scientists — Scientist 1 describes a global dust cloud causing cooling, and Scientist 2 describes SO₂ cooling followed by CO₂ warming. D represents Scientist 1's hypothesis specifically and would be rejected by Scientist 2. On agreement questions, look for claims that appear in the shared introduction or that both viewpoints independently accept.

The correct answer is D (greater than 8.5 s). The passage establishes that higher viscosity means greater resistance to flow — the ball drops more slowly — producing a longer drop time. At 40°C, Oil W has the highest viscosity of the four oils tested at 115.0 mPa·s, and it produced the longest drop time of 8.5 s. Oil V has a viscosity of 130.0 mPa·s — higher than Oil W. Therefore, the ball must take longer to fall through Oil V than through Oil W, making the drop time greater than 8.5 s. F and G describe drop times associated with lower-viscosity oils at 40°C. H describes a range between Oil Y and Oil W values — too low. Pro tip: anchor extrapolation questions by identifying the highest or lowest tested value and reasoning beyond it.

This is a defense of argument question asking how a scientist would respond to criticism. Scientist 3's core claim is that Newtonian gravity works at solar system scales (high acceleration) but fails at galactic scales ("accelerations are incredibly low < 10⁻¹⁰ m/s²"). The natural defense against "you're changing physics" is "we've never actually tested physics at these extreme conditions." Choice A correctly predicts this defense—the untested regime justifies modification. Choice B (WIMPs detected) would support Scientist 1, not defend Scientist 3. Choice C (light emission) is irrelevant to gravity laws. Choice D (universe age) is irrelevant. Pro tip: Use a scientist's core argument to predict their defense against criticism.

This is a prediction question requiring you to apply classification principles. The Introduction defines ectotherms as animals that "rely on external heat sources to regulate their body temperature." Since frogs are ectotherms (stated in the question), they should behave like the other ectotherm in the study—the Lizard. The Lizard's metabolic rate increases with environmental temperature because ectotherms become more physiologically active as they warm up (their enzymes work faster, chemical reactions speed up). Choice B correctly predicts the Frog would resemble the Lizard's increasing curve. Choice A (Mouse curve) would apply to endotherms, not ectotherms. Choices C and D (horizontal, vertical) aren't biologically realistic. Pro tip: When predicting behavior of organisms in the same category, expect similar patterns.