How to find the height of of an acute / obtuse isosceles triangle - ACT Math

Card 0 of 18

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

What is the height of an isosceles triangle which has a base of and an area of ?

Answer

The area of a triangle is given by the equation:

$\small A=\frac{1}{2}bh$

In this case, we are given the area ( $\small A$ ) and the base ( $\small b$ ) and are asked to solve for height ( $\small h$ ).

To do this, we must plug in the given values for $\small A$ and $\small b$ , which gives the following:

$\small 24;cm^2=\frac{1}{2}(4; cm)h$

We then must multiply the right side, and then divide the entire equation by 2, in order to solve for $\small h$ :

$\small 24;cm^2=2;cm(h)$

$\small \frac{24; cm^2}{2; cm}=\frac{2; cm(h)}{2; cm}$

$\small 12;cm=h$

$\small h=12;cm$

Therefore, the height of the triangle is $\small 12;cm$ .

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

What is the height of an isosceles triangle which has a base of and an area of ?

Answer

The area of a triangle is given by the equation:

$\small A=\frac{1}{2}bh$

In this case, we are given the area ( $\small A$ ) and the base ( $\small b$ ) and are asked to solve for height ( $\small h$ ).

To do this, we must plug in the given values for $\small A$ and $\small b$ , which gives the following:

$\small 24;cm^2=\frac{1}{2}(4; cm)h$

We then must multiply the right side, and then divide the entire equation by 2, in order to solve for $\small h$ :

$\small 24;cm^2=2;cm(h)$

$\small \frac{24; cm^2}{2; cm}=\frac{2; cm(h)}{2; cm}$

$\small 12;cm=h$

$\small h=12;cm$

Therefore, the height of the triangle is $\small 12;cm$ .

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

What is the height of an isosceles triangle which has a base of and an area of ?

Answer

The area of a triangle is given by the equation:

$\small A=\frac{1}{2}bh$

In this case, we are given the area ( $\small A$ ) and the base ( $\small b$ ) and are asked to solve for height ( $\small h$ ).

To do this, we must plug in the given values for $\small A$ and $\small b$ , which gives the following:

$\small 24;cm^2=\frac{1}{2}(4; cm)h$

We then must multiply the right side, and then divide the entire equation by 2, in order to solve for $\small h$ :

$\small 24;cm^2=2;cm(h)$

$\small \frac{24; cm^2}{2; cm}=\frac{2; cm(h)}{2; cm}$

$\small 12;cm=h$

$\small h=12;cm$

Therefore, the height of the triangle is $\small 12;cm$ .

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

What is the height of an isosceles triangle which has a base of and an area of ?

Answer

The area of a triangle is given by the equation:

$\small A=\frac{1}{2}bh$

In this case, we are given the area ( $\small A$ ) and the base ( $\small b$ ) and are asked to solve for height ( $\small h$ ).

To do this, we must plug in the given values for $\small A$ and $\small b$ , which gives the following:

$\small 24;cm^2=\frac{1}{2}(4; cm)h$

We then must multiply the right side, and then divide the entire equation by 2, in order to solve for $\small h$ :

$\small 24;cm^2=2;cm(h)$

$\small \frac{24; cm^2}{2; cm}=\frac{2; cm(h)}{2; cm}$

$\small 12;cm=h$

$\small h=12;cm$

Therefore, the height of the triangle is $\small 12;cm$ .

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

What is the height of an isosceles triangle which has a base of and an area of ?

Answer

The area of a triangle is given by the equation:

$\small A=\frac{1}{2}bh$

In this case, we are given the area ( $\small A$ ) and the base ( $\small b$ ) and are asked to solve for height ( $\small h$ ).

To do this, we must plug in the given values for $\small A$ and $\small b$ , which gives the following:

$\small 24;cm^2=\frac{1}{2}(4; cm)h$

We then must multiply the right side, and then divide the entire equation by 2, in order to solve for $\small h$ :

$\small 24;cm^2=2;cm(h)$

$\small \frac{24; cm^2}{2; cm}=\frac{2; cm(h)}{2; cm}$

$\small 12;cm=h$

$\small h=12;cm$

Therefore, the height of the triangle is $\small 12;cm$ .

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

What is the height of an isosceles triangle which has a base of and an area of ?

Answer

The area of a triangle is given by the equation:

$\small A=\frac{1}{2}bh$

In this case, we are given the area ( $\small A$ ) and the base ( $\small b$ ) and are asked to solve for height ( $\small h$ ).

To do this, we must plug in the given values for $\small A$ and $\small b$ , which gives the following:

$\small 24;cm^2=\frac{1}{2}(4; cm)h$

We then must multiply the right side, and then divide the entire equation by 2, in order to solve for $\small h$ :

$\small 24;cm^2=2;cm(h)$

$\small \frac{24; cm^2}{2; cm}=\frac{2; cm(h)}{2; cm}$

$\small 12;cm=h$

$\small h=12;cm$

Therefore, the height of the triangle is $\small 12;cm$ .

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

What is the height of an isosceles triangle which has a base of and an area of ?

Answer

The area of a triangle is given by the equation:

$\small A=\frac{1}{2}bh$

In this case, we are given the area ( $\small A$ ) and the base ( $\small b$ ) and are asked to solve for height ( $\small h$ ).

To do this, we must plug in the given values for $\small A$ and $\small b$ , which gives the following:

$\small 24;cm^2=\frac{1}{2}(4; cm)h$

We then must multiply the right side, and then divide the entire equation by 2, in order to solve for $\small h$ :

$\small 24;cm^2=2;cm(h)$

$\small \frac{24; cm^2}{2; cm}=\frac{2; cm(h)}{2; cm}$

$\small 12;cm=h$

$\small h=12;cm$

Therefore, the height of the triangle is $\small 12;cm$ .

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

What is the height of an isosceles triangle which has a base of and an area of ?

Answer

The area of a triangle is given by the equation:

$\small A=\frac{1}{2}bh$

In this case, we are given the area ( $\small A$ ) and the base ( $\small b$ ) and are asked to solve for height ( $\small h$ ).

To do this, we must plug in the given values for $\small A$ and $\small b$ , which gives the following:

$\small 24;cm^2=\frac{1}{2}(4; cm)h$

We then must multiply the right side, and then divide the entire equation by 2, in order to solve for $\small h$ :

$\small 24;cm^2=2;cm(h)$

$\small \frac{24; cm^2}{2; cm}=\frac{2; cm(h)}{2; cm}$

$\small 12;cm=h$

$\small h=12;cm$

Therefore, the height of the triangle is $\small 12;cm$ .

Compare your answer with the correct one above

Question

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

Answer

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

Compare your answer with the correct one above

Question

What is the height of an isosceles triangle which has a base of and an area of ?

Answer

The area of a triangle is given by the equation:

$\small A=\frac{1}{2}bh$

In this case, we are given the area ( $\small A$ ) and the base ( $\small b$ ) and are asked to solve for height ( $\small h$ ).

To do this, we must plug in the given values for $\small A$ and $\small b$ , which gives the following:

$\small 24;cm^2=\frac{1}{2}(4; cm)h$

We then must multiply the right side, and then divide the entire equation by 2, in order to solve for $\small h$ :

$\small 24;cm^2=2;cm(h)$

$\small \frac{24; cm^2}{2; cm}=\frac{2; cm(h)}{2; cm}$

$\small 12;cm=h$

$\small h=12;cm$

Therefore, the height of the triangle is $\small 12;cm$ .

Compare your answer with the correct one above

Tap the card to reveal the answer

How to find the height of of an acute / obtuse isosceles triangle - ACT Math

An isosceles triangle has a base of and an area of . What must be the height of this triangle?

.

What is the height of an isosceles triangle which has a base of and an area of ?

An isosceles triangle has a base of and an area of . What must be the height of this triangle?

.

What is the height of an isosceles triangle which has a base of and an area of ?

An isosceles triangle has a base of and an area of . What must be the height of this triangle?

.

What is the height of an isosceles triangle which has a base of and an area of ?

An isosceles triangle has a base of and an area of . What must be the height of this triangle?

.

What is the height of an isosceles triangle which has a base of and an area of ?

An isosceles triangle has a base of and an area of . What must be the height of this triangle?

.

What is the height of an isosceles triangle which has a base of and an area of ?

An isosceles triangle has a base of and an area of . What must be the height of this triangle?

.

What is the height of an isosceles triangle which has a base of and an area of ?

An isosceles triangle has a base of and an area of . What must be the height of this triangle?

.

What is the height of an isosceles triangle which has a base of and an area of ?

An isosceles triangle has a base of and an area of . What must be the height of this triangle?

.

What is the height of an isosceles triangle which has a base of and an area of ?

An isosceles triangle has a base of and an area of . What must be the height of this triangle?

.

What is the height of an isosceles triangle which has a base of and an area of ?

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$

An isosceles triangle has a base of $12\ cm$ and an area of $42\ cm^{2}$ . What must be the height of this triangle?

$A=\frac{1}{2}bh$ .

$6x=42$

$x=7$