Logarithms - ACT Math
Card 0 of 189
Evaluate
log327
Evaluate
log327
You can change the form to
3_x_ = 27
x = 3
You can change the form to
3_x_ = 27
x = 3
Compare your answer with the correct one above
How can we simplify this expression below into a single logarithm?

How can we simplify this expression below into a single logarithm?
Using the property that
, we can simplify the expression to
.
Given that
and 
We can further simplify this equation to 
Using the property that , we can simplify the expression to
.
Given that and
We can further simplify this equation to
Compare your answer with the correct one above
If
, then
?
If , then
?

Calculate the power of
that makes the expression equal to 25. We can set up an alternate or equivalent equation to solve this problem:

Solve this equation by taking the square root of both sides.


, because logarithmic equations cannot have a negative base.
The solution to this expression is:

Calculate the power of that makes the expression equal to 25. We can set up an alternate or equivalent equation to solve this problem:
Solve this equation by taking the square root of both sides.
, because logarithmic equations cannot have a negative base.
The solution to this expression is:
Compare your answer with the correct one above
If log4 x = 2, what is the square root of x?
If log4 x = 2, what is the square root of x?
Given log4_x_ = 2, we can determine that 4 to the second power is x; therefore the square root of x is 4.
Given log4_x_ = 2, we can determine that 4 to the second power is x; therefore the square root of x is 4.
Compare your answer with the correct one above
Solve for x in the following equation:
log224 - log23 = log_x_27
Solve for x in the following equation:
log224 - log23 = log_x_27
Since the two logarithmic expressions on the left side of the equation have the same base, you can use the quotient rule to re-express them as the following:
log224 – log23 = log2(24/3) = log28 = 3
Therefore we have the following equivalent expressions, from which it can be deduced that x = 3.
log_x_27 = 3
_x_3 = 27
Since the two logarithmic expressions on the left side of the equation have the same base, you can use the quotient rule to re-express them as the following:
log224 – log23 = log2(24/3) = log28 = 3
Therefore we have the following equivalent expressions, from which it can be deduced that x = 3.
log_x_27 = 3
_x_3 = 27
Compare your answer with the correct one above
Let log 5 = 0.69897 and log 2 = 0.30103. Solve log 50
Let log 5 = 0.69897 and log 2 = 0.30103. Solve log 50
Using properties of logs:
log (xy) = log x + log y
log (_x_n) = n log x
log 10 = 1
So log 50 = log (10 * 5) = log 10 + log 5 = 1 + 0.69897 = 1.69897
Using properties of logs:
log (xy) = log x + log y
log (_x_n) = n log x
log 10 = 1
So log 50 = log (10 * 5) = log 10 + log 5 = 1 + 0.69897 = 1.69897
Compare your answer with the correct one above
y = 2x
If y = 3, approximately what is x?
Round to 4 decimal places.
y = 2x
If y = 3, approximately what is x?
Round to 4 decimal places.
To solve, we use logarithms. We log both sides and get: log3 = log2x
which can be rewritten as log3 = xlog2
Then we solve for x: x = log 3/log 2 = 1.5850 . . .
To solve, we use logarithms. We log both sides and get: log3 = log2x
which can be rewritten as log3 = xlog2
Then we solve for x: x = log 3/log 2 = 1.5850 . . .
Compare your answer with the correct one above
If
, what is
?
If , what is
?
Use the following equation to easily manipulate all similar logs:
changes to
.
Therefore,
changes to
.
2 raised to the power of 6 yields 64, so
must equal 6. If finding the 6 was difficult from the formula, simply keep multiplying 2 by itself until you reach 64.
Use the following equation to easily manipulate all similar logs:
changes to
.
Therefore, changes to
.
2 raised to the power of 6 yields 64, so must equal 6. If finding the 6 was difficult from the formula, simply keep multiplying 2 by itself until you reach 64.
Compare your answer with the correct one above
Which of the following is a value of
that satisfies
?
Which of the following is a value of that satisfies
?
The general equation of a logarithm is
, and 
In this case,
, and thus
(or
, but
is not an answer choice)
The general equation of a logarithm is , and
In this case, , and thus
(or
, but
is not an answer choice)
Compare your answer with the correct one above
If
, what is
?
If , what is
?
If
, then 


If , then
Compare your answer with the correct one above
What value of
satisfies the equation
?
What value of satisfies the equation
?
The answer is
.
can by rewritten as
.
In this form the question becomes a simple exponent problem. The answer is
because
.
The answer is .
can by rewritten as
.
In this form the question becomes a simple exponent problem. The answer is because
.
Compare your answer with the correct one above
If
,
then what is
?
If
,
then what is ?
This is a test of translating logarithmic/exponential properties, with the key here being to realize that
is equivalent to
.
With that in mind, here is how it works out:
![4^{5/2} = (\sqrt[2]{4})^{5} = 2^{5} = 2*2*2*2*2 = 32](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/481209/gif.latex)
Hence,
.
This is a test of translating logarithmic/exponential properties, with the key here being to realize that
is equivalent to
.
With that in mind, here is how it works out:
Hence, .
Compare your answer with the correct one above
What is the value of
? Round to the nearest hundredth.
What is the value of ? Round to the nearest hundredth.
You could solve this by using your calculator. Remember that you will have to translate this into:

Another way you can solve it is by noticing that 
This means you can rewrite your logarithm:

Applying logarithm rules, you can factor out the power:

For any value
,
. Therefore,
. So, your answer is
.
You could solve this by using your calculator. Remember that you will have to translate this into:
Another way you can solve it is by noticing that
This means you can rewrite your logarithm:
Applying logarithm rules, you can factor out the power:
For any value ,
. Therefore,
. So, your answer is
.
Compare your answer with the correct one above
Solve for 
.
Round to the nearest hundredth.
Solve for
.
Round to the nearest hundredth.
To solve an exponential equation like this, you need to use logarithms. This can be translated into:

Now, remember that your calculator needs to have this translated. The logarithm
is equal to the following:
, which equals approximately
.
Remember that you have the equation:

Thus,
.
To solve an exponential equation like this, you need to use logarithms. This can be translated into:
Now, remember that your calculator needs to have this translated. The logarithm is equal to the following:
, which equals approximately
.
Remember that you have the equation:
Thus, .
Compare your answer with the correct one above
Solve the following equation
.
Solve the following equation
.
In order to solve a question like this, you will need to use logarithms. First, start by converting this into a basic logarithm:

Recall that you need to convert
for your calculator:
, which equals approximately 
Thus, you can solve for
:



In order to solve a question like this, you will need to use logarithms. First, start by converting this into a basic logarithm:
Recall that you need to convert for your calculator:
, which equals approximately
Thus, you can solve for :
Compare your answer with the correct one above
What is the value of
? Round to the nearest hundredth.
What is the value of ? Round to the nearest hundredth.
Remember that you will need to calculate your logarithm by doing a base conversion. This is done by changing
into:

Using your calculator, you can find this to be:
or approximately 
Remember that you will need to calculate your logarithm by doing a base conversion. This is done by changing into:
Using your calculator, you can find this to be:
or approximately
Compare your answer with the correct one above
At the end of each year, an account compounds interest at a rate of
. If the account began with
, how many years will it take for it to reach a value of
, presuming no withdrawals or deposits occur?
At the end of each year, an account compounds interest at a rate of . If the account began with
, how many years will it take for it to reach a value of
, presuming no withdrawals or deposits occur?
The general function that defines this compounding interest is:
, where
is the number of years.
What we are looking for is:

You can solve this using a logarithm. First, isolate the variable term by dividing both sides:

Which is:

Next, recall that this is the logarithm:

For this, you will need to do a base conversion:

This is 
This means that it will take
years.
is too few and at the end of
, you will have over
.
The general function that defines this compounding interest is:
, where
is the number of years.
What we are looking for is:
You can solve this using a logarithm. First, isolate the variable term by dividing both sides:
Which is:
Next, recall that this is the logarithm:
For this, you will need to do a base conversion:
This is
This means that it will take years.
is too few and at the end of
, you will have over
.
Compare your answer with the correct one above
can be written as which of the following?
A. 
B. 
C. 
can be written as which of the following?
A.
B.
C.
A is true in two ways. You can use the fact that if a logarithm has no base, you can use base 10, or you can use the fact that you can use this property:

B is a simple change of base application, and C is simply computing the logarithm.



A is true in two ways. You can use the fact that if a logarithm has no base, you can use base 10, or you can use the fact that you can use this property:
B is a simple change of base application, and C is simply computing the logarithm.
Compare your answer with the correct one above
if
, what is
?
if , what is
?
The first step of this problem is to find
by expanding to the formula

y is found to be 2. The next step is to plug y in to the second log.
, which expands to


The first step of this problem is to find
by expanding to the formula
y is found to be 2. The next step is to plug y in to the second log.
, which expands to
Compare your answer with the correct one above
Find
.
Find .

expands to


expands to

expands to
expands to
Compare your answer with the correct one above