6th Grade Math · Question of the Day

6th Grade Math Question of the Day

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Thursday, September 17, 2026

Use a measurement interpretation: How many pieces of length $\tfrac{1}{4}$ foot fit into $\tfrac{2}{3}$ foot? Compute $\left(\tfrac{2}{3}\right)\div\left(\tfrac{1}{4}\right)$ .

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Question of the Day

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Use a measurement interpretation: How many pieces of length $\tfrac{1}{4}$ foot fit into $\tfrac{2}{3}$ foot? Compute $\left(\tfrac{2}{3}\right)\div\left(\tfrac{1}{4}\right)$ .

$\tfrac{8}{3}$ (correct answer)
$\tfrac{2}{12}=\tfrac{1}{6}$
$\tfrac{1}{6}$
$\tfrac{3}{8}$

Explanation: This question tests dividing fractions $(a/b) \div (c/d)$ using the reciprocal method (multiply by $d/c$ ), with a measurement interpretation of how many smaller lengths fit into a larger one. Compute $(2/3) \div (1/4) = (2/3) \times 4/1 = (2 \times 4)/(3 \times 1) = 8/3$ . Verification: $(1/4) \times (8/3) = (1 \times 8)/(4 \times 3) = 8/12 = 2/3$ foot, matching the total. This means $8/3$ pieces of $1/4$ foot fit into $2/3$ foot, more than 2 full pieces. Common mistakes include dividing numerators and denominators separately to get $3/8$ as in choice D, or arithmetic errors like $2/12 = 1/6$ . Method: flip divisor, multiply, calculate, simplify if needed, verify. Visual: a number line from 0 to $2/3$ marked in $1/4$ increments shows $8/3$ segments.