Divide Multi-Digit Numbers - 6th Grade Math

$1111$. Each digit is $9$, and $9 div 9 = 1$ for each place value.

$a=bq+r$ with $0\le r<b$. This equation verifies division: dividend equals divisor times quotient plus remainder.

$182$. $12$ goes into $21$ once, into $98$ eight times, and into $24$ twice.

$720$. $7$ divides evenly: $5040 = 7 imes 720$.

$120$. $12$ goes into $14$ once, into $24$ twice, and into $0$ zero times.

$104$. $9$ goes into $93$ ten times, then into $36$ four times exactly.

$1869$. $3$ divides evenly: $5607 = 3 imes 1869$.

$168$. $6$ divides evenly: $1008 = 6 imes 168$.

$105$. $7$ goes into $73$ ten times, into $35$ five times.

$146$. Remainder $18 > 3$ (divisor), so continue dividing: $438 \div 3 = 146$.

$288$. $8$ goes into $23$ twice, into $70$ eight times, into $64$ eight times.

$819$. $5$ goes into $40$ eight times, into $9$ once, into $45$ nine times.

$648$. $9$ goes into $58$ six times, into $43$ four times, into $72$ eight times.

$1{,}336,R^1$. $6$ goes into $80$ thirteen times with $2$ left, into $21$ three times, into $37$ six times.

$208$. $6$ goes into $12$ twice, into $4$ zero times, into $48$ eight times.

$87,R20$. $40$ goes into $350$ eight times with $30$ left, into $300$ seven times.

$504$. $12$ goes into $60$ five times, into $4$ zero times, into $48$ four times.

$640$. $15$ goes into $96$ six times, into $60$ four times, into $0$ zero times.

$4$. After $8 \times 8 = 64$, subtract to get $3$, bring down $2$ to get $32 \div 8 = 4$.

Divide the leftmost digits: $8 \div 6$. Start with the leftmost digit(s) that form a number $\geq$ divisor.

A digit of the quotient. Each digit shows how many times the divisor fits into that portion.

The leftover amount: $3$ not evenly divisible by $5$. The remainder is what's left after dividing evenly.

Check: $(\text{divisor}\times\text{quotient})+\text{remainder}=\text{dividend}$. Multiply quotient by divisor, add remainder to verify.

Remainder $<$ divisor. The remainder must always be less than what you're dividing by.