4th Grade Math - Solving for Length

What is the length of a rectangular room with a perimeter of and a width of

Explanation

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

Subtract from both sides

Divide by both sides

$\frac{50}{2}=\frac{2l}{2}$

What is the length of a rectangular yard with an area of and a width of

Explanation

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$15=l\times 3$

$\frac{15}{3}=\frac{l\times 3}{3}$

What is the length of a rectangular room with a perimeter of and a width of

Explanation

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

Subtract from both sides

Divide by both sides

$\frac{64}{2}=\frac{2l}{2}$

What is the length of a rectangular room with a perimeter of and a width of

Explanation

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

Subtract from both sides

Divide by both sides

$\frac{28}{2}=\frac{2l}{2}$

What is the length of a yard with a perimeter of and a width of

Explanation

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

Subtract from both sides

Divide by both sides

$\frac{14}{2}=\frac{2l}{2}$

What is the length of a yard with a perimeter of and a width of

Explanation

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

Subtract from both sides

Divide by both sides

$\frac{10}{2}=\frac{2l}{2}$

What is the length of a room with a perimeter of and a width of

Explanation

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

Subtract from both sides

Divide by both sides

$\frac{20}{2}=\frac{2l}{2}$

What is the length of a rectangular room with an area of and a width of

Explanation

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$63=l\times 9$

$\frac{63}{9}=\frac{l\times 9}{9}$

What is the length of a rectangular room with an area of and a width of

Explanation

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$90=l\times 15$

$\frac{90}{15}=\frac{l\times 15}{15}$

What is the length of a rectangular yard with an area of and a width of

Explanation

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$8=l\times 4$

$\frac{8}{4}=\frac{l\times 4}{4}$

Solving for Length

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