Removing Discontinuities Practice Test

For $p(x)=\begin{cases}\dfrac{x^2-5x+6}{x-2},&x\ne2\\1,&x=2\end{cases}$, what value should replace $1$ to make $p$ continuous at $x=2$?

For $p(x)=\begin{cases}\dfrac{x^2-16}{x-4},&x\ne4\\10,&x=4\end{cases}$, what value should replace $10$ to make $p$ continuous at $x=4$?