Exploring Behaviors of Implicit Relations Practice Test

$\dfrac{dy}{dx}=\dfrac{1-\cos(xy),y}{\cos(xy),x-1}$

$\dfrac{dy}{dx}=\dfrac{\cos(xy),y-1}{\cos(xy),x-1}$

$\dfrac{dy}{dx}=\dfrac{\cos(xy)}{1}$

$\dfrac{dy}{dx}=\dfrac{1-\cos(xy),x}{\cos(xy),y-1}$

$\dfrac{dy}{dx}=\dfrac{\cos(xy)(y+x\dfrac{dy}{dx})-1}{1}$