AP Biology Quiz: Mendelian Genetics
20 questions · exam conditions
0:00
Mendelian GeneticsQuestion 1 of 20

A genetic counselor is analyzing a pedigree for a rare genetic condition. Two unaffected parents have a child who is affected by the condition.

The inheritance pattern of this condition is most likely which of the following?

Autosomal recessive
Autosomal dominant
X-linked dominant
Y-linked
← Back to quizzes

AP Biology Quiz

AP Biology Quiz: Mendelian Genetics

Practice Mendelian Genetics in AP Biology with focused quiz questions that help you check what you know, review explanations, and build confidence with test-style prompts.

What this quiz covers

This quiz focuses on Mendelian Genetics, giving you a quick way to practice the rules, question types, and explanations that matter most for AP Biology.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

All questions

Question 1

A genetic counselor is analyzing a pedigree for a rare genetic condition. Two unaffected parents have a child who is affected by the condition.

The inheritance pattern of this condition is most likely which of the following?

  1. Autosomal recessive (correct answer)
  2. Autosomal dominant
  3. X-linked dominant
  4. Y-linked
Explanation: When two unaffected individuals have an affected offspring, it is a classic sign of a recessive inheritance pattern. The parents must both be heterozygous carriers of the recessive allele. If the trait were dominant, at least one parent would have to be affected to pass the allele to the child.

Question 2

In a species of plant, the allele for tall stems (TT) is dominant to short stems (tt), and the allele for red flowers (RR) is dominant to white flowers (rr). The genes for stem height and flower color are on different chromosomes.

If two plants that are heterozygous for both traits are crossed, what fraction of the offspring is expected to be tall with white flowers?

  1. 1/161/16
  2. 3/43/4
  3. 3/163/16 (correct answer)
  4. 9/169/16
Explanation: In a cross of TtRr×TtRrTtRr \times TtRr, the probability of a tall offspring (TT-) is 3/43/4, and the probability of a white-flowered offspring (rrrr) is 1/41/4. Using the product rule for independent events, the probability of an offspring being tall and white is (3/4)×(1/4)=3/16(3/4) \times (1/4) = 3/16.

Question 3

In tomato plants, red fruit (RR) is dominant to yellow fruit (rr), and tall vines (TT) are dominant to dwarf vines (tt). The genes are unlinked.

A plant that is heterozygous for both traits is crossed with a plant that has yellow fruit and dwarf vines. What is the expected phenotypic ratio of the offspring?

  1. 9 red/tall : 3 red/dwarf : 3 yellow/tall : 1 yellow/dwarf
  2. 3 red/tall : 1 yellow/dwarf
  3. 1 red/tall : 1 red/dwarf : 1 yellow/tall : 1 yellow/dwarf (correct answer)
  4. 1 red/tall : 1 yellow/dwarf
Explanation: This is a dihybrid test cross (RrTt×rrttRrTt \times rrtt). The heterozygous parent produces four types of gametes (RT,Rt,rT,rtRT, Rt, rT, rt) in equal proportion. The homozygous recessive parent produces only one type of gamete (rtrt). The resulting offspring will have four different genotypes (RrTt,Rrtt,rrTt,rrttRrTt, Rrtt, rrTt, rrtt) and four corresponding phenotypes, each in equal proportion, leading to a 1:1:1:1 ratio.

Question 4

A pedigree chart traces the inheritance of a particular genetic disorder in a family. Affected individuals are represented by shaded symbols. The disorder appears in every generation and is passed from an affected father to his son.

Based on this information, what is the most likely mode of inheritance for this disorder?

  1. Autosomal recessive
  2. X-linked dominant
  3. X-linked recessive
  4. Autosomal dominant (correct answer)
Explanation: The disorder appearing in every generation suggests a dominant pattern. The transmission from father to son rules out X-linked inheritance, as a father passes his Y chromosome, not his X, to his son. Therefore, the pattern is most consistent with autosomal dominant inheritance.

Question 5

In fruit flies, the allele for long wings (LL) is dominant to the allele for vestigial wings (ll). A researcher has a male fruit fly with long wings but an unknown genotype.

To determine the genotype of the long-winged male fly, the researcher should perform a test cross. This involves crossing the male fly with a female of which of the following genotypes?

  1. A female with vestigial wings, genotype llll (correct answer)
  2. A female with long wings, known to be homozygous dominant, genotype LLLL
  3. A female with long wings, known to be heterozygous, genotype LlLl
  4. A female from the same parental generation as the male fly, whose genotype is also unknown
Explanation: A test cross is used to determine an unknown genotype of an organism showing the dominant phenotype. This is done by crossing the organism with a homozygous recessive individual. The phenotypes of the offspring will reveal the unknown genotype.

Question 6

In snapdragons, the allele for red flowers is completely dominant over the allele for white flowers. A botanist has a large population of red-flowered snapdragons.

Which of the following statements about this population is most accurate?

  1. The population must be homozygous for the flower color gene because all individuals express the same trait.
  2. The population contains individuals with one genotype but may have two different phenotypes for flower color.
  3. The genotypes of the plants cannot be determined without performing a test cross on every individual in the population.
  4. The population contains individuals with at least two different genotypes but only one phenotype for flower color. (correct answer)
Explanation: Because red is dominant, the red-flowered phenotype can be produced by both the homozygous dominant (RRRR) and heterozygous (RrRr) genotypes. Therefore, the population of red-flowered plants can contain individuals with two different genotypes while exhibiting only one phenotype.

Question 7

In a plant species, three genes are unlinked. Tall (TT) is dominant to short (tt), purple flowers (PP) are dominant to white (pp), and round seeds (RR) are dominant to wrinkled (rr).

In a cross between two plants with genotype TtPpRrTtPpRr, what is the probability of an offspring being short, having purple flowers, and having wrinkled seeds?

  1. 1/641/64
  2. 3/643/64 (correct answer)
  3. 9/649/64
  4. 27/6427/64
Explanation: For each gene, the cross is between two heterozygotes. The probability of short (tttt) is 1/41/4. The probability of purple flowers (PP-) is 3/43/4. The probability of wrinkled seeds (rrrr) is 1/41/4. Since the genes are unlinked, the probabilities are multiplied: (1/4)×(3/4)×(1/4)=3/64(1/4) \times (3/4) \times (1/4) = 3/64.

Question 8

A dominant plant is testcrossed. If it is heterozygous, what is the probability that all 6 offspring are dominant?

  1. 1/641/64 (correct answer)
  2. 1/321/32
  3. 1/161/16
  4. 1/81/8
Explanation: In a testcross with a heterozygous dominant plant, each offspring has a 1/2 chance of showing the dominant phenotype. For all 6 offspring to be dominant, multiply 1/2 six times: 1/64. The tempting 1/32 is wrong because it uses five offspring instead of six.

Question 9

In AaBb × AaBb, what fraction of offspring showing both dominant traits are heterozygous at both loci?

  1. 1/41/4
  2. 2/32/3
  3. 4/94/9 (correct answer)
  4. 1/91/9
Explanation: Of the 16 offspring from AaBb x AaBb, 9 show both dominant traits (A_B_). Among those 9, the genotypes are 1 AABB, 2 AABb, 2 AaBB, and 4 AaBb. So 4 out of 9 dominant-phenotype offspring are heterozygous at both loci. The tempting 1/4 is the fraction of all offspring that are AaBb, not the fraction among dominant-phenotype offspring.

Question 10

Two heterozygotes have two children. What is the probability the children have the same phenotype?

  1. 9/169/16
  2. 1/21/2
  3. 1/161/16
  4. 5/85/8 (correct answer)
Explanation: Each child from two heterozygotes has a 3/4 chance of showing the dominant phenotype and a 1/4 chance of showing the recessive phenotype. The children have the same phenotype if both are dominant (3/4 x 3/4 = 9/16) or both are recessive (1/4 x 1/4 = 1/16). Add those: 9/16 + 1/16 = 10/16 = 5/8. The tempting 9/16 only counts both dominant and forgets the both-recessive case.

Question 11

A father has a recessive phenotype; his daughter has the dominant phenotype. What must be true of the mother?

  1. Must be homozygous dominant
  2. Must be heterozygous genotype
  3. Must carry a dominant allele (correct answer)
  4. Must be homozygous recessive
Explanation: The father's recessive phenotype means his genotype is aa, so he passes an a allele to his daughter. Since your daughter shows the dominant phenotype, she must have at least one A allele, and it has to come from her mother. So the mother only has to carry a dominant allele; she could be AA or Aa. The tempting mistake is assuming she must be heterozygous, but a homozygous dominant mother also works.

Question 12

Two carriers of an autosomal recessive disorder have three children. What is the chance exactly one is affected?

  1. 9/649/64
  2. 27/6427/64 (correct answer)
  3. 9/169/16
  4. 3/43/4
Explanation: For each child, the chance of being affected is 1/4 and unaffected is 3/4. Exactly one affected among three can happen in 3 orders, each with probability (1/4)(3/4)^2 = 9/64. Multiply by 3 to get 27/64. The tempting wrong answer 9/64 is only the chance for one specific birth order.

Question 13

In corn, smooth kernels (K) are completely dominant to wrinkled kernels (k). A plant with smooth kernels is self-fertilized, and the offspring show a 3 smooth : 1 wrinkled phenotype ratio. Assume one autosomal gene with complete dominance and no linkage to other genes. Which genotype must the parent plant have had?

Which parental genotype is required to produce a 3:13:1 smooth-to-wrinkled ratio by self-crossing?

  1. KK
  2. Kk (correct answer)
  3. kk
  4. KK or Kk
  5. Kk or kk
Explanation: This question tests Mendelian inheritance analysis, requiring inference of parental genotype from self-cross offspring ratios. The 3:1 smooth-to-wrinkled ratio indicates the parent is heterozygous Kk, as self-fertilization (Kk x Kk) produces KK, Kk, and kk genotypes. Alleles segregate equally into gametes, yielding 1/4 KK, 1/2 Kk (smooth), and 1/4 kk (wrinkled), for a 3:1 phenotypic ratio. This fits because only a heterozygote can produce both dominant and recessive phenotypes in that proportion. A tempting distractor is KK or Kk, which might stem from thinking homozygotes could yield recessives, ignoring that KK self-cross gives all smooth. For inheritance questions, work backward from ratios to parental genotypes using standard Mendelian patterns like 3:1 for heterozygote self-crosses.

Question 14

In snapdragons, tall stems (T) are completely dominant to short stems (t). A tall plant of unknown genotype is crossed with a short plant (tt). In the offspring, 48 plants are tall and 52 plants are short. Assume random fertilization and a single gene with complete dominance. Which genotype is most likely for the tall parent?

  1. TT
  2. Tt (correct answer)
  3. tt
  4. Either TT or tt
  5. Either TT or Tt in a 3:1 ratio
Explanation: This question tests the skill of analyzing Mendelian inheritance patterns. The cross between a tall snapdragon of unknown genotype and a short one (tt) yields approximately equal numbers of tall and short offspring, indicating a 1:1 phenotypic ratio. This ratio suggests the tall parent is heterozygous (Tt), as it produces gametes with 1/2 T and 1/2 t, combining with the t gametes from the short parent to give Tt and tt equally. If the tall parent were homozygous (TT), all offspring would be tall, but the observed data matches the segregation expected from a heterozygous parent. A tempting distractor is TT, which might arise from the misconception that dominant phenotypes always indicate homozygous genotypes without considering test cross results. To solve similar inheritance questions, use test crosses with recessive individuals to reveal unknown genotypes through offspring ratios.

Question 15

In fruit flies, red eyes (R) are completely dominant to sepia eyes (r). Two red-eyed flies are crossed, and both are known to be heterozygous (Rr × Rr). Each fly produces gametes carrying one allele, and fertilization is random. Assume a single gene controls eye color with complete dominance. Which genotype ratio is expected among the offspring?

  1. 1 RR : 2 Rr : 1 rr (correct answer)
  2. 3 RR : 1 rr
  3. 1 Rr : 1 rr
  4. 3 Rr : 1 rr
  5. All Rr
Explanation: This question tests the skill of analyzing Mendelian inheritance patterns. In the cross between two heterozygous red-eyed fruit flies (Rr × Rr), each parent produces gametes with 1/2 R and 1/2 r alleles due to independent segregation. The Punnett square reveals offspring genotypes of RR, Rr, and rr in a 1:2:1 ratio, directly reflecting the combination of alleles from random fertilization. This classic monohybrid ratio confirms the expected genotypic distribution. A tempting distractor is 3 RR : 1 rr, which might stem from the misconception of equating genotypic ratios with phenotypic ones by ignoring the heterozygous category. To solve similar inheritance questions, calculate genotypic ratios using Punnett squares and distinguish them from phenotypic ratios based on dominance.

Question 16

In rabbits, long ears (L) are completely dominant to short ears (l). A breeder crosses a homozygous dominant rabbit (LL) with a heterozygous rabbit (Ll). Each offspring inherits one allele from each parent, and the gene shows complete dominance. Which proportion of offspring is expected to be heterozygous (Ll)?

  1. 14\tfrac{1}{4}
  2. 12\tfrac{1}{2} (correct answer)
  3. 34\tfrac{3}{4}
  4. All offspring
  5. No offspring
Explanation: This question tests the skill of analyzing Mendelian inheritance patterns. In the cross between a homozygous dominant long-eared rabbit (LL) and a heterozygous one (Ll), the LL parent produces only L gametes, while the Ll parent produces 1/2 L and 1/2 l. Offspring genotypes are LL from L + L combinations and Ll from L + l, each occurring with 1/2 probability due to segregation. Therefore, half of the offspring are expected to be heterozygous (Ll), as the recessive allele appears in half the gametes from the heterozygous parent. A tempting distractor is 3/4, which could arise from the misconception of applying a monohybrid ratio without accounting for one parent's homozygosity. To solve similar inheritance questions, identify gamete probabilities for each parent and use them to compute specific genotypic proportions.

Question 17

In dogs, curly fur (C) is completely dominant to straight fur (c), and black coat color (B) is completely dominant to brown coat color (b). Two dogs with genotypes CcBb are crossed (CcBb × CcBb), and the genes assort independently. Assume complete dominance for both traits. Which proportion of offspring is expected to show straight fur and brown coat?

  1. 116\tfrac{1}{16} (correct answer)
  2. 316\tfrac{3}{16}
  3. 916\tfrac{9}{16}
  4. 14\tfrac{1}{4}
  5. 18\tfrac{1}{8}
Explanation: This question tests the skill of analyzing Mendelian inheritance patterns. In the dihybrid cross between two CcBb dogs (CcBb × CcBb), each trait follows monohybrid segregation: 1/4 cc for straight fur and 1/4 bb for brown coat. Since the genes assort independently, the combined probability for both recessive phenotypes (cc and bb) is 1/4 × 1/4 = 1/16. This reflects the random combination of alleles during fertilization for unlinked genes. A tempting distractor is 9/16, which could stem from the misconception of calculating the dominant phenotype ratio instead of the double recessive one. To solve similar inheritance questions, break down dihybrid crosses into monohybrid components and multiply probabilities for independent events.

Question 18

In corn, smooth kernels (S) are completely dominant to wrinkled kernels (s). A plant with genotype SS is crossed with a plant with genotype ss. Each offspring receives one allele from each parent. Assume a single gene controls kernel texture and inheritance is Mendelian with complete dominance. Which outcome is expected among the offspring?

  1. All offspring are wrinkled (ss)
  2. All offspring are smooth (Ss) (correct answer)
  3. 12\tfrac{1}{2} smooth and 12\tfrac{1}{2} wrinkled
  4. 34\tfrac{3}{4} smooth and 14\tfrac{1}{4} wrinkled
  5. All offspring are smooth (SS)
Explanation: This question tests the skill of analyzing Mendelian inheritance patterns. In the cross between a homozygous smooth-kernel corn plant (SS) and a homozygous wrinkled one (ss), the SS parent produces only S gametes, while the ss parent produces only s gametes. All offspring receive one S and one s allele, resulting in the heterozygous Ss genotype, which expresses the dominant smooth phenotype due to complete dominance. Thus, all offspring are expected to have smooth kernels, as no homozygous recessive combinations occur. A tempting distractor is 3/4 smooth and 1/4 wrinkled, which could come from the misconception of assuming both parents are heterozygous like in a monohybrid cross. To solve similar inheritance questions, determine gamete types from each parent's genotype and predict outcomes using principles of dominance and segregation.

Question 19

In a plant, red petals (R) are completely dominant to white petals (r), and round seeds (S) are completely dominant to wrinkled seeds (s). A plant heterozygous for both traits (RrSs) is testcrossed with a plant homozygous recessive for both traits (rrss). Assume independent assortment. Which proportion of offspring is expected to have white petals and wrinkled seeds?

  1. 1/16
  2. 1/8
  3. 1/4 (correct answer)
  4. 1/2
  5. 3/4
Explanation: This problem tests understanding of dihybrid testcrosses using Mendelian genetics with independent assortment. In RrSs × rrss, the heterozygous parent produces four gamete types (RS, Rs, rS, rs) in equal proportions (1/4 each), while the homozygous recessive parent only produces rs gametes. The offspring genotypes are RrSs, Rrss, rrSs, and rrss, each occurring at 1/4 frequency. The rrss offspring (white petals, wrinkled seeds) represent 1/4 of the total. A common mistake is multiplying 1/2 × 1/2 to get 1/4, which works here but for the wrong reason—in testcrosses, offspring ratios directly reflect the heterozygous parent's gamete ratios. For dihybrid testcrosses, each phenotype class appears at 1/4 frequency when genes assort independently.

Question 20

In pea plants, purple flowers (P) are completely dominant to white (p). A plant with purple flowers that is heterozygous (Pp) is crossed with a white-flowered plant (pp). Each offspring receives one allele for flower color from each parent. Assuming Mendelian segregation and no linkage to other traits, the offspring phenotypes depend only on whether they inherit at least one P allele. Which proportion of offspring is expected to have white flowers?​​​

  1. All offspring will have white flowers
  2. Three-fourths of offspring will have white flowers
  3. One-half of offspring will have white flowers (correct answer)
  4. One-fourth of offspring will have white flowers
  5. No offspring will have white flowers
Explanation: This question tests your ability to predict offspring phenotypes using Mendelian inheritance principles. In this cross between Pp (purple) × pp (white), the heterozygous parent produces two types of gametes: P and p in equal proportions, while the homozygous recessive parent only produces p gametes. The possible offspring genotypes are Pp (purple) and pp (white), each occurring with 50% probability since half the gametes from the Pp parent carry p. Therefore, one-half of offspring will have white flowers (pp genotype). A common error is thinking all offspring will be white because one parent is white, but this ignores that the Pp parent contributes a dominant P allele half the time. When solving inheritance problems, always construct a Punnett square to systematically track all possible gamete combinations.