All questions
Question 1
What is the x-value of the solution to the system: 3x+y=14 and x−y=2?
- 2
- 4 (correct answer)
- 8
- 12
Explanation: This is a systems of equations question testing the elimination method. Choice B (4) is correct — add the two equations to eliminate y: (3x + y) + (x − y) = 14 + 2 → 4x = 16 → x = 4. (If desired, verify: y = x − 2 = 2, and 3(4) + 2 = 14 ✓.) Choice A (2) is the y-value, not x — the student may have solved for y and stopped, or substituted back into the wrong equation. Choice C (8) comes from solving 4x = 16 as x = 16/2 = 8, dividing by 2 instead of 4. Choice D (12) likely comes from adding the right-hand sides to get 16, then adding 14 − 2 = 12 via some misalignment. Pro tip: When one variable has matching coefficients with opposite signs (y and −y here), adding the equations eliminates that variable immediately. Always double-check by substituting both values back into BOTH original equations.
Question 2
Tickets to a high school play cost $12 for adults and $8 for children. On opening night, 150 tickets were sold and total revenue was $1,440. How many more children's tickets were sold than adult tickets?
- 30 (correct answer)
- 45
- 60
- 90
Explanation: This is a systems of equations word problem testing multi-step algebraic modeling. Choice A (30) is correct — set up: let A = adult tickets and C = children's tickets. Two equations: A + C = 150 (total tickets) and 12A + 8C = 1,440 (total revenue). Solve by substitution: C = 150 − A → 12A + 8(150 − A) = 1,440 → 12A + 1,200 − 8A = 1,440 → 4A = 240 → A = 60. Then C = 150 − 60 = 90. Difference: C − A = 90 − 60 = 30. Choice B (45) likely comes from an arithmetic error mid-solve, perhaps computing 4A = 180 → A = 45. Choice C (60) reports the number of adult tickets — finding A but not completing the final step (finding the difference). Choice D (90) reports the number of children's tickets — finding C but not subtracting A. Pro tip: Systems word problems require a final step after solving for variables. Read the question again carefully — here it asks "how many MORE children's tickets," which means C − A, not just C or A alone. After solving the system, always return to the original question to make sure you're reporting the right quantity.
Question 3
A taxi charges a $3 flat fee plus $2 per mile. Another taxi charges a $1 flat fee plus $3 per mile. For what number of miles x do the two taxis cost the same (in dollars)?
{y=2x+3y=3x+1- 1
- 2 (correct answer)
- 3
- 4
Explanation: Set the costs equal to find when taxis charge the same. We have 2x + 3 = 3x + 1. Subtract 2x from both sides: 3 = x + 1. Subtract 1 from both sides: x = 2. At 2 miles, both taxis cost $7.
Question 4
If 2x+3y=13 and 2x−3y=1, what is the value of y?
- 1
- 2 (correct answer)
- 3
- 4
Explanation: Use the elimination method by adding 2x+3y=13 and 2x−3y=1. This eliminates y, giving 4x=14, so x=14/4=3.5. Substitute into 2x−3y=1: 2(3.5)−3y=1, 7−3y=1, −3y=−6, y=2. Alternatively, subtract the equations to get 6y=12, y=2 directly. Choice C of 3 might come from misadding to 4x=12. Question 5
Solve the system of equations:
{5x−y=142x+y=7
What is the solution (x,y)?
- (3,1) (correct answer)
- (2,3)
- (1,3)
- (3,−1)
Explanation: Use elimination by adding the equations directly. Adding 5x - y = 14 and 2x + y = 7 gives 7x = 21, so x = 3. Substitute x = 3 into 2x + y = 7: 2(3) + y = 7, so y = 1. The solution is (3, 1).
Question 6
Solve the system:
{x+2y=103x−2y=6
Which ordered pair satisfies both equations?
- (4,3) (correct answer)
- (2,4)
- (3,4)
- (4,2)
Explanation: Use elimination: add equations x+2y=10 and 3x−2y=6. The y terms cancel, giving 4x=16, so x=4. Substitute x=4 into x+2y=10: 4+2y=10, so y=3. The solution is (4,3). Question 7
Consider the system of equations below: 3x+2y=12 and y=x−4. What is the value of x+y for the solution to this system?
- 0
- 2
- 4 (correct answer)
- 8
Explanation: This is a systems of equations question testing substitution. Choice C (4) is correct — substitute y = x − 4 into the first equation: 3x + 2(x − 4) = 12 → 5x − 8 = 12 → 5x = 20 → x = 4. Plug back in: y = 4 − 4 = 0. Therefore x + y = 4 + 0 = 4. Choice A (0) reports only y = 0 rather than x + y. Choice B (2) results from an arithmetic error in solving 5x = 20 — possibly dividing by 10 instead of 5. Choice D (8) finds x = 4 correctly but then substitutes incorrectly into the second equation, using y = x instead of y = x − 4, giving y = 4 and x + y = 8. Pro tip: After finding one variable in a system, always substitute back into the equation that contains BOTH variables to find the second. And re-read what the question asks — here it's asking for x + y, not just x or y individually.
Question 8
Consider the system of linear equations: 3x−y=11 and 2x+y=9. What is the value of x in the solution to this system?
- 2
- 4 (correct answer)
- 5
- 8
Explanation: The correct answer is B (4). Add the two equations to eliminate y: (3x − y) + (2x + y) = 11 + 9 → 5x = 20 → x = 4. Check: substitute x = 4 into the second equation: 2(4) + y = 9 → y = 1. Verify in first: 3(4) − 1 = 11 ✓. A (2) confuses x and y — the student may find y = 1 and misread it. C (5) results from an arithmetic error when adding the equations: computing 11 + 9 = 25 instead of 20. D (8) comes from a substitution error. Elimination by addition works here because the y terms (+y and −y) cancel perfectly.
Question 9
If the system below is true, what is the value of y?
{3x+4y=16x−4y=11- −45
- −43 (correct answer)
- 45
- 43
Explanation: Use elimination by adding the equations. Adding 3x + 4y = 1 and 6x - 4y = 11 gives 9x = 12, so x = 4/3. Substitute into 3x + 4y = 1: 3(4/3) + 4y = 1, which gives 4 + 4y = 1, so 4y = -3 and y = -3/4.
Question 10
What is the solution (x,y) to the system x+y=6 and 2x−y=3?
- (4, 2)
- (2, 4)
- (1, 5)
- (3, 3) (correct answer)
Explanation: Use elimination to solve this system. Adding the equations x + y = 6 and 2x - y = 3 eliminates y: 3x = 9, so x = 3. Substituting x = 3 into the first equation: 3 + y = 6, so y = 3. The solution is (3, 3).
Question 11
If x+y=8 and x−y=4, what is the value of x?
- 5
- 6 (correct answer)
- 4
- 7
Explanation: Use elimination to solve this system. Adding x+y=8 and x−y=4 eliminates y: 2x=12, so x=6. Substituting into x+y=8: 6+y=8, so y=2. Therefore, x=6. Question 12
For what value of k, if any, does the system of equations below have no solution?2x+3y=6 6x+ky=7
- 2
- 3
- 9 (correct answer)
- There is no such value of k.
Explanation: Systems of equations have no solution when the lines are parallel—same slope but different y-intercepts. Convert the first equation to slope-intercept form: y=−2x/3+2 (slope = −2/3). For the second equation: y=−6x/k+7/k (slope = −6/k). Set the slopes equal: −6/k=−2/3, which gives k=9. Verify the y-intercepts are different: 2=7/9 ✓, confirming the lines are parallel. This is a conceptual question testing whether you understand what "no solution" means geometrically. Question 13
Solve the system:
{x+y=83x−y=4
What is the solution (x,y)?
- (1,7)
- (4,4)
- (2,6)
- (3,5) (correct answer)
Explanation: Use elimination: Add the equations x+y=8 and 3x−y=4. This gives 4x=12, so x=3. Substitute x=3 into x+y=8: 3+y=8, so y=5. The solution is (3,5). Question 14
Solve the system:
{4x+y=92x−y=3
Which ordered pair satisfies both equations?
- (1,5)
- (2,1) (correct answer)
- (3,−3)
- (1,−5)
Explanation: Use elimination: Add the equations 4x+y=9 and 2x−y=3. This gives 6x=12, so x=2. Substitute x=2 into 2x−y=3: 4−y=3, so y=1. The solution is (2,1). Question 15
A taxi charges a flat fee plus a per-mile rate. A 4-mile ride costs $14 and a 7-mile ride costs $20. If x is the flat fee and y is the cost per mile, what is (x,y)?
- (2,3)
- (6,2) (correct answer)
- (8,1)
- (4,27)
Explanation: Set up the system where x is flat fee and y is per-mile rate: x+4y=14 and x+7y=20. Subtract the first from the second: 3y=6, so y=2. Substitute back: x+4(2)=14, so x=6. The solution is (6,2). Question 16
If 4x+2y=18 and 2x−y=1, what is the value of y?
- 2
- 3
- 4 (correct answer)
- 5
Explanation: Use the substitution method from 2x - y = 1, so y = 2x - 1, into 4x + 2y = 18. This gives 4x + 2(2x - 1) = 18, 4x + 4x - 2 = 18, 8x = 20, x = 2.5, y = 2(2.5) - 1 = 5 - 1 = 4. The value of y is 4. Choice B of 3 might come from solving 8x = 18 incorrectly.
Question 17
Consider the system of equations below: 3x+2y=12 and y=x−4. What is the value of x+y for the solution to this system?
- 0
- 2
- 4 (correct answer)
- 8
Explanation: This is a systems of equations question testing substitution. Choice C (4) is correct — substitute y = x − 4 into the first equation: 3x + 2(x − 4) = 12 → 5x − 8 = 12 → 5x = 20 → x = 4. Plug back in: y = 4 − 4 = 0. Therefore x + y = 4 + 0 = 4. Choice A (0) reports only y = 0 rather than x + y. Choice B (2) results from an arithmetic error in solving 5x = 20 — possibly dividing by 10 instead of 5. Choice D (8) finds x = 4 correctly but then substitutes incorrectly into the second equation, using y = x instead of y = x − 4, giving y = 4 and x + y = 8. Pro tip: After finding one variable in a system, always substitute back into the equation that contains BOTH variables to find the second. And re-read what the question asks — here it's asking for x + y, not just x or y individually.
Question 18
If 4x+y=10 and 2x−y=2, what is the value of x?
- 1
- 2 (correct answer)
- 3
- 4
Explanation: Use elimination to solve this system. Add the two equations: (4x + y) + (2x - y) = 10 + 2, which gives 6x = 12, so x = 2. This matches choice B.
Question 19
Two numbers have sum 13 and difference 5. If x+y=13 and x−y=5, what is (x,y)?
- (7,6)
- (4,9)
- (8,5)
- (9,4) (correct answer)
Explanation: Use elimination to solve this system with x+y=13 and x−y=5. Adding the equations eliminates y: 2x=18, so x=9. Substitute back: 9+y=13, so y=4. The solution is (9,4). Question 20
What is the solution (x,y) to the system x+y=9 and x−y=1?
- (7, 2)
- (6, 3)
- (4, 5)
- (5, 4) (correct answer)
Explanation: Use elimination to solve this system. Adding x + y = 9 and x - y = 1 eliminates y: 2x = 10, so x = 5. Substituting into x + y = 9: 5 + y = 9, so y = 4. The solution is (5, 4).